Use the Virial theorem to show the following...

GravityX
Messages
19
Reaction score
1
Homework Statement
I have to show the following with the virial theorem ##E=\langle \cal H \rangle_k## ##=k_bT \sum\limits_{i=1}^{N}a_i##
Relevant Equations
none
The expression ##\langle \cal H \rangle_k## is the expected value of the canonical ensemble.

The Hamiltonian is defined as follows, with the scaling ##\lambda##

##\lambda \cal H ## : ##\lambda H(x_1, ...,x_N)=H(\lambda^{a_1}x_1,....,\lambda^{a_N}x_N)##

As a hint, I should differentiate the Hamiltonian with respect to ##\lambda##

Unfortunately, I don't know how exactly I should do this, i.e. form the derivative, I have now proceeded in such a way that I have formed the differential

$$H(\lambda^{a_1}x_1,...\lambda^{a_N}x_N)=\lambda^{a_1}x_1\frac{\partial H}{\partial x_1}+...\lambda^{a_N}x_N\frac{\partial H}{\partial x_N}$$

Then the derivative should look like this,

$$\frac{\partial}{\partial \lambda}H(\lambda^{a_1}x_1,...\lambda^{a_N}x_N)=a_1\lambda^{a_1-1}x_1\frac{\partial H}{\partial x_1}+...a_N\lambda^{a_N-1}x_N\frac{\partial H}{\partial x_N}$$

Is this correct
 
Physics news on Phys.org
Not entirely. Just take the total derivative of the equation
$$\lambda H(x_1,\ldots,x_N)=H(\lambda^{a_1} x_1,\ldots,\lambda^{a_N} x_N).$$
Your last equation is correct.

Next you have to think about, what
$$\left \langle x_k \frac{\partial H}{\partial x_k} \right \rangle$$
might be. For that start with the definition of how to take expectation values in the canonical ensemble. It's not too easy, and maybe you are allowed to use the result, which is the "virial theorem".
 
Thank you vanhees71 for your help and sorry I'm only getting back to you now, I had two weeks Christmas break 🎅

I was able to solve the problem now, the expression ##\Bigl\langle x_k\frac{\partial H }{\partial x_k} \Bigr\rangle## we had stated in the lecture as ##k_bT##.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top