Use the work-energy theorem to derive an expression for v^2

[David112234]

Homework Statement

Homework Equations

Work energy theorem

The Attempt at a Solution

.5mv² - .5mv² = (kx - μmg)d
final velocity is 0

½mv² =(kx - μmg)d
solve for v²

((kx - μmg)d2)m
When this was wrong I tried integrating Fx but it was still wrong

 

[BvU]

I miss a question in this problem statement ?
I miss what $k$ means (but I can guess)
I also miss what $x$ means, which is very important. Note that there is a $d$ already.

 

[David112234]

I miss a question in this problem statement ?
I miss what $k$ means (but I can guess)
I also miss what $x$ means, which is very important. Note that there is a $d$ already.

K is the spring constant
X is supposed to be d, I am just used to using x for position, in answers 3-4 i changed it to d

 

[haruspex]

K is the spring constant
X is supposed to be d, I am just used to using x for position, in answers 3-4 i changed it to d

If x is d, your very first equation is wrong.
Remeber that there is energy in the spring both initially and after the mass has moved distance d. What is the change in that energy?