Using an integrating factor properly

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The discussion revolves around solving the differential equation dy/dt - 2y = 4 - t using an integrating factor, specifically e^(-2t). The user expresses confusion after applying the integrating factor and attempts to simplify the equation. Another participant clarifies that the simplification to d(ye^(-2t))/dt can be achieved by applying the product rule. This highlights the importance of understanding integration techniques and the product rule in solving differential equations. The conversation emphasizes the need for clarity in the steps of integration and simplification.
cameuth
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alright guys, I've been trying to tackle this for a couple of hours now.

dy/dt-2y=4-t
my integrating factor is e^(-2t) of course.

dy(e^(-2t))/dt-2ye^(-2t)=4e^(-2t)-te^(-2t)

then I get completely lost. how do I integrate when it's like this? My book simplifies the above equation into

d(e^(-2y))/dt=4e^(-2t)-te^(-2t)

can anyone explain how that simplification occurs??
 
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hi cameuth! :smile:

(try using the X2 button just above the Reply box :wink:)
cameuth said:
d(e^(-2y))/dt=4e^(-2t)-te^(-2t)

can anyone explain how that simplification occurs??

(you mean d(ye-2t)/dt :wink:)

use the product rule on ye-2t :smile:
 

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