Using chain rule to derive the path equation

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SUMMARY

The discussion focuses on using the chain rule to derive the path equation for a system defined by the equations r' = 4r - rf and f' = -3f + rf. Participants successfully identified critical points and derived the linearized system but encountered challenges in deriving the path equation. The key relationship established is dr/df = (4r - rf)/(-3f - rf), which serves as a foundation for further analysis. The hint provided emphasizes utilizing the linearized system to assist in deriving the path equation.

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  • Understanding of differential equations and phase plane analysis
  • Familiarity with the chain rule in calculus
  • Knowledge of critical points and linearization techniques
  • Basic concepts of trajectory analysis in dynamical systems
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  • Study the application of the chain rule in deriving path equations in dynamical systems
  • Learn about linearization techniques for nonlinear systems
  • Explore phase plane analysis and trajectory behavior in differential equations
  • Investigate critical point classification and stability analysis
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helpinghand
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r' = 4r - rf
f' = -3f + rf

In this question, there was three parts:
a) find all the critical points of this system.
b) Derive the linearised system about each critcal point...
c) Use the chain rule to derive the path equation of the trajectories in the phase plane.

I managed to get a and b out.

For c:

dr/df = dr/dt . dt/df

=> dr/df = (4r - rf)/(-3f - rf) ~~ not sure what to do from here.

I'm not sure how to get the path equation... Anyone have ideas?

Cheers
 
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hi helpinghand! :smile:
helpinghand said:
r' = 4r - rf
f' = -3f + rf

a) find all the critical points of this system.
b) Derive the linearised system about each critcal point...
c) Use the chain rule to derive the path equation of the trajectories in the phase plane.

hint: for (c), use (b) :wink:
 

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