Using density to find the % composition of an alloy

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SUMMARY

The discussion focuses on calculating the mass composition of an alloy, specifically plumber's solder, which consists of tin and lead. The densities of tin (7.3 g/cm³) and lead (11.3 g/cm³) are provided, along with the density of the alloy (9.7 g/cm³). The initial calculation assumed the percentage of lead to be X%, leading to an incorrect conclusion of 60% lead and 40% tin, while the correct values are 30.1% tin and 69.9% lead. The discrepancy arises from the ambiguity in defining percentage composition, which can refer to weight percent (wt%) or atomic percent (at%).

PREREQUISITES
  • Understanding of density and its units (g/cm³)
  • Basic algebra for solving equations
  • Knowledge of weight percent (wt%) and atomic percent (at%) definitions
  • Familiarity with alloy composition calculations
NEXT STEPS
  • Study the principles of alloy density calculations
  • Learn about weight percent vs. atomic percent in material science
  • Explore methods for determining the composition of mixtures
  • Investigate common alloys and their properties
USEFUL FOR

Chemistry students, materials scientists, and anyone involved in metallurgy or alloy composition analysis will benefit from this discussion.

Kushal
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Homework Statement



The densities (at 25*C) of tin and lead are 7.3 g/cm3 and 11.3 g/cm3 respectively. Plumber's solder is an alloy of tin and lead and has a density of 9.7 g/cm3.

Estimate the composition by mass, of the two metals in this solder.

Homework Equations





The Attempt at a Solution



i assumed the % composition of lead to be X%. so % composition of tin is (100 - X)%.
using [(X*11.3)/100] + [((100-X)*7.3)/100] = 9.7

i got % lead as 60% and % tin as 40%.

but the answers from the book are 30.1% for tin and 69.9% for lead.

any help!
 
Physics news on Phys.org
Amount fractions can be measured in weight percent (wt%) or atomic percent (at%), so just writing "%" is ambiguous. Perhaps this explains the difference.
 

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