1. The problem statement, all variables and given/known data What currents are provided by the batteries? What is the voltage drop across the 1.2 Ω resistor? 2. Relevant equations V = IR Junction Rule = sum of current at a junction = 0 Loop Rule = sum of changes in potential around any closed path of a circuit must be 0 3. The attempt at a solution I hope what I've drawn is clear enough. I 1 only goes around the small rectangle whereas I 2 encompasses the entire rectangle. The current provided by the 12 V battery using the loop rule: 12 V + (3.9 Ω)(I1)+(1.2 Ω)(I1) + (9.8 Ω)(I1) = 0 Does that make sense? I'm unsure when it comes to these rules.