Using PMI prove un=((-1)^(n+1))/3 + (2^n)/3

Thread starter AerospaceEng
Start date Aug 30, 2011

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SUMMARY

The discussion centers on solving the recurrence relation using the Principle of Mathematical Induction (PMI). The correct formulation of the sequence is given by u_n = \frac{(-1)^{n+1}+2^n}{3} and u_{n-1} = \frac{(-1)^n+2^{n-1}}{3}. The participants confirm that the solution was achieved by applying the induction hypothesis appropriately, leading to a successful resolution of the problem.

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Aug 30, 2011

AerospaceEng

Solved thank you.

Thank you for all the help just a little forgetful mistake.

Last edited: Aug 30, 2011

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Aug 30, 2011

micromass

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You didn't use the induction hypothesis yet. You need to sub

[tex]u_n = \frac{(-1)^{n+1}+2^n}{3}[/tex]

and

[tex]u_{n-1} = \frac{(-1)^n+2^{n-1}}{3}[/tex]