MHB Using quadratic zeroes to find value of parameter

Click For Summary
The discussion focuses on using quadratic equations to determine the values of parameters \(\alpha\) and \(\beta\) based on their relationships with \(p\) and \(q\). The equations presented indicate that the product of the roots \(r\) is equal to \(\alpha\beta\). Participants are encouraged to manipulate the quadratic equations to isolate \(\alpha\) and \(\beta\) in terms of the given parameters. The goal is to find non-zero solutions for both variables. This approach aims to clarify the connections between the parameters and the roots of the quadratic equations.
Mathsonfire
Messages
11
Reaction score
0
https://uploads.tapatalk-cdn.com/20180712/28a4bbb89e76d3478ae2fd0825562148.jpg
Question 81
 
Mathematics news on Phys.org
Re: Help

Do you have any thoughts on how to begin?
 
Since there's been no reply, let's get started by observing that we must have:

$$r=\alpha\beta$$

Now, to express \(\alpha\) and \(\beta\) in terms of \(p\) and \(q\) I would look at:

$$\alpha^2-p\alpha+r=\frac{\alpha^2}{4}-q\frac{\alpha}{2}+r$$

$$\beta^2-p\beta+r=4\beta^2-2q\beta+r$$

Solve the first equation for the non-zero value of \(\alpha\) and solve the second equation for the non-zero value of \(\beta\)...what do you find?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K