Using quadratic zeroes to find value of parameter

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SUMMARY

The discussion focuses on using quadratic equations to determine the values of parameters \(\alpha\) and \(\beta\) in relation to \(p\) and \(q\). The equations presented are \(\alpha^2 - p\alpha + r = \frac{\alpha^2}{4} - q\frac{\alpha}{2} + r\) and \(\beta^2 - p\beta + r = 4\beta^2 - 2q\beta + r\). Participants are encouraged to solve these equations for non-zero values of \(\alpha\) and \(\beta\) to derive insights into the relationships between the parameters. The discussion emphasizes the importance of understanding the roots of quadratic equations in parameter estimation.

PREREQUISITES
  • Understanding of quadratic equations and their properties
  • Familiarity with algebraic manipulation techniques
  • Knowledge of parameter estimation in mathematical modeling
  • Basic proficiency in solving polynomial equations
NEXT STEPS
  • Explore the derivation of quadratic formula solutions
  • Study the implications of parameter estimation in statistical models
  • Learn about the role of discriminants in determining the nature of roots
  • Investigate applications of quadratic equations in real-world scenarios
USEFUL FOR

Mathematicians, students studying algebra, and professionals involved in statistical modeling or data analysis will benefit from this discussion.

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Question 81
 
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Re: Help

Do you have any thoughts on how to begin?
 
Since there's been no reply, let's get started by observing that we must have:

$$r=\alpha\beta$$

Now, to express \(\alpha\) and \(\beta\) in terms of \(p\) and \(q\) I would look at:

$$\alpha^2-p\alpha+r=\frac{\alpha^2}{4}-q\frac{\alpha}{2}+r$$

$$\beta^2-p\beta+r=4\beta^2-2q\beta+r$$

Solve the first equation for the non-zero value of \(\alpha\) and solve the second equation for the non-zero value of \(\beta\)...what do you find?
 

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