Show that using small volumes of ether solvent in an extraction from aqueous phase is better than using larger volumes. The total volume of organic solvent, amount of material to extract, aqueous volume and distribution constant are the same. You can do this with an equation or words.
Kdistribution = g/100mL ether layer / g/100mL aqueous layer
The Attempt at a Solution
So say we have 10 small samples of 10g ether and then 2 big samples of 100g ether. Our aqueous phase is constant at 100g lets say.
So, 10/100 = .1 = K
Since there are 10 extraction .1 x 10 = 1
on the other hand, 2 big samples of 100g ether
I'm guessing the distribution constant is better when it's lower so that's why small samples of ether are used. I have a feeling I'm approaching this question completely wrong though.