Using the Definition of the Derivative, Find the Derivative

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Homework Help Overview

The discussion revolves around finding derivatives using various approaches, including the definition of the derivative and the quotient rule. Participants are exploring the mathematical reasoning behind their attempts and clarifying concepts related to derivatives.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the derivative of g(t) = 1 / sqrt(t) using the definition of the derivative, expressing confusion about the steps taken in a referenced solution. Other participants question the application of certain algebraic manipulations and suggest exploring the multiplication of terms to clarify the reasoning.
  • Another poster seeks to find the derivative of t / (t - 1)^2 using the quotient rule, expressing uncertainty about the simplification of their result. Participants discuss factoring techniques and the difference of squares as a means to understand the simplification process.
  • A third poster presents a problem involving the derivative of cot(x) / e^t, leading to a discussion about variable consistency and the importance of maintaining the same variable throughout the problem.

Discussion Status

Contextual Notes

Some participants mention gaps in their recent math education, which may affect their confidence in handling the problems. There is also a note about the importance of using consistent variables in derivative problems.

communitycoll
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Homework Statement


Using the definition of the derivative, find the derivative of g(t) = 1 / sqrt(t).

Homework Equations


I was told I could solve it by rationalizing it. I asked a question on Yahoo! Answers and saw someone work it out step by step, but I don't understand any of why they did what they did. If it's painfully obvious, and it's just a matter of knowing how to do some easy algebra please forgive me; it's been a little over a year since my last math class.

The Attempt at a Solution


The Yahoo! Answers person's attempt at the solution that is.

g'(t) = lim[h→0] (g(t+h) − g(t)) / h

g'(t) = lim[h→0] (1/√(t+h) − 1/√(t)) / h

g'(t) = lim[h→0] √(t+h)√(t) * (1/√(t+h) − 1/√(t)) / (h √(t+h)√(t))

I don't understand this ^ step because I don't know where √(t+h)√(t) is coming from, or why it's also being applied to the denominator.

g'(t) = lim[h→0] (√(t) − √(t+h)) / (h √(t+h)√(t))

I don't understand how multiplying the numerator by √(t+h)√(t) got √(t) − √(t+h) either. After this point I think I understand what they're doing.

g'(t) = lim[h→0] (√(t) − √(t+h)) (√(t) + √(t+h)) / (h √(t+h)√(t) (√(t) + √(t+h)))

g'(t) = lim[h→0] (t − (t+h) / (h √(t+h)√(t) (√(t) + √(t+h)))

g'(t) = lim[h→0] −h / (h √(t+h)√(t) (√(t) + √(t+h)))

g'(t) = lim[h→0] −1 / (√(t+h)√(t) (√(t) + √(t+h)))

g'(t) = −1 / (√(t)√(t) (√(t) + √(t)))

g'(t) = −1 / (t * 2√(t))

g'(t) = −1 / (2t^(3/2))
 
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As a general rule, you don't want fractions on top of fractions. Your helper multiplied the numerator by something they knew would get rid of the fractions there (the product of the denominators of those fractions). They also had to multiply the denominator by the same quantity so that what they did was a fancy way of multiplying by 1 - i.e. they did nothing, but in a way that left the equation simpler. It's perhaps easier to see typeset:
[tex] \frac{1/\sqrt{t+h} − 1/\sqrt{t}}{h}= <br /> \left(\frac{\sqrt{t+h}\sqrt{t}}{\sqrt{t+h}\sqrt{t}}\right)\left(\frac{1/\sqrt{t+h} − 1/\sqrt{t}}{h}\right)[/tex]
 
I don't understand this ^ step because I don't know where √(t+h)√(t) is coming from, or why it's also being applied to the denominator.
It's being applied to the numerator because it is also being applied to the denominator ;) the choice for the multiplier was to get rid of the fraction as Ibix said.
I don't understand how multiplying the numerator by √(t+h)√(t) got √(t) − √(t+h) either.
Did you try multiplying it out to see?

Note: [tex]\frac{1}{a}-\frac{1}{b} = \frac{b-a}{ab}[/tex]
 
Alrighty then. I get it now. Thanks to the both of you.
 
No worries.
 

Homework Statement


I need to find the derivative of t / (t - 1)^2 (not using the definition though). I need to use quotient rule.

Homework Equations


I got (-t^2 + 1) / (t - 1)^4, which Wolfram Alpha says can be simplified to -(t+1) / (t-1)^3, which is what people are telling me the answer is. I don't understand how it simplifies to that though, which is what I need to be explained.

The Attempt at a Solution


I already have the solution in an unsimplified form, so there.
 
communitycoll said:

Homework Statement


I need to find the derivative of t / (t - 1)^2 (not using the definition though). I need to use quotient rule.

Homework Equations


I got (-t^2 + 1) / (t - 1)^4, which Wolfram Alpha says can be simplified to -(t+1) / (t-1)^3, which is what people are telling me the answer is. I don't understand how it simplifies to that though, which is what I need to be explained.

The Attempt at a Solution


I already have the solution in an unsimplified form, so there.
Do you know how to factor the difference of squares?
 
SammyS said:
Do you know how to factor the difference of squares?

I probably used to : D but it's been awhile, as I took precal my junior year and nothing my senior year of HS. Is it just a matter of looking up a Khan Academy video?
 
(a - b)(a + b) = a2 - b2

Work with -t2 + 1 a bit to get

-t2 + 1 = 1 - t2 = (1 - t)(1 + t) .
 
  • #10
Okay-dokey. I remember that now. Thank you, it's just that it's been a good long while since I've been in a math class : D I appreciate it.
 
  • #11

Homework Statement


Find the derivative of cot(x) / e^t.

Homework Equations


Using the quotient rule:

-[csc^2(x) + cot(x)] / e^t.

Wolfram Alpha tells me that it's [-e^(-t)][csc^2(x)], not using the quotient rule:

http://www.wolframalpha.com/input/?i=derivative+(cot+x)+/+e^t

The Attempt at a Solution


Just the function plugged into the quotient rule.
 
  • #12
First of all, it's better to start a new thread with a different problem.

Secondly, you have two different variables, t and x. From your answer, I suspect you meant to use a single variable. If you change the t to an x in both Wolfram and your answer, then the answers will match.
 
  • #13
Ah, terribly sorry. Didn't realize that : D Thank you. Also I just figured people wouldn't want me spamming up the forum. I'll start a new thread next time. Muchas gracias.
 

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