Utlilizing Dalton's Law of Partial Pressures

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SUMMARY

The discussion focuses on calculating the partial pressure of oxygen when it is transferred from a 2.0 L container at 3 Atmospheres to a 5.0 L container of hydrogen, also at 3 Atmospheres. Using Dalton's Law of Partial Pressures and the ideal gas law (PV=nRT), the pressure of oxygen decreases proportionally due to the increase in volume, resulting in a new partial pressure of 1.2 Atmospheres. The total pressure in the new container, combining the partial pressures of both gases, is calculated to be 4.2 Atmospheres.

PREREQUISITES
  • Understanding of Dalton's Law of Partial Pressures
  • Familiarity with the ideal gas law (PV=nRT)
  • Basic knowledge of gas behavior under varying volumes and pressures
  • Ability to perform calculations involving pressure and volume
NEXT STEPS
  • Study the implications of Dalton's Law in multi-gas systems
  • Learn advanced applications of the ideal gas law in real-world scenarios
  • Explore the effects of temperature changes on gas pressure
  • Investigate the behavior of gases in varying container sizes and shapes
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Chemistry students, educators, and professionals in fields involving gas laws and thermodynamics will benefit from this discussion.

Integral0
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If a 2.0 L container of oxygen at 3 Atmospheres of pressure is poured into a 5.0 L container of Hydrogen at 3 atmospheres of pressure. What is the partial pressure of oxygen in new container? What is the new total pressure in the container?

I'm not sure how to start this . . . if you could help me, I'd appreciate it.
 
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If a 2.0 L container of oxygen at 3 Atmospheres of pressure is poured into a 5.0 L container of Hydrogen at 3 atmospheres of pressure. What is the partial pressure of oxygen in new container? What is the new total pressure in the container?

Pressure is the only dependent variable in the gas law equation PV=nRT and is determined by temperature, volume, and the amount of gas. So, here is a practical way to do this problem.

We know that a certain amount of oxygen, due to its energy, in a fixed volume exerts a certain pressure. If we are to increase the volume from 2.0L to 5.0L the pressure will decrease proportionally since we are only changing one variable. We decrease the pressure by 2.5. 3/2.5=1.2 atm. Add this to the pressure of hydrogen, 3 and you get 4.2 atm.
 
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