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I am at my wit's end so I hope someone can help.
I am trying to do what is (almost) the simplest SUSY calculation one can think of: the calculation of the vacuum energy in the Wess-Zumino model. The result shoudl be zero but I don't get that.
Since SUSY is "beyond the standard model" physics, I decided to cross-post my question here.
Let me start by asking a simpler question and see if anyone can help.
Let me break up the Wess-Zumino interactions into four terms
[tex] L_1 = - \frac{1}{2} g^2 (A^2 + B^2)^2 [/tex]
[tex] L_2 = - M g (A^3 + A B^2) [/tex]
[tex] L_3 = - g A \overline{\Psi} \Psi[/tex]
[tex] L_4 = - ig B \overline{\Psi} \gamma_5 \Psi [/tex]
where A and B are scalar fields and Psi is a Majorana spinor, although for the terms I want to check in this post, this makes no difference, they can be treated as Dirac spinors.
I consider the contributions to the vacuum energy of order g^2 so I calculate the time
ordered expectation values of
[tex] i L_1 - \frac{1}{2} ( L_2^2 + L_3^2 + L_4^2 + 2 L_2 L_3 + 2 L_2 L_4 + 2 L_3 L_4 ) [/tex]
There are two main classes of diagrams: diagrams in which three lines connect two distinct points.
(i.e. "sunset" diagrams). These are a bit more tricky.
Simpler diagrams are those that contain two loops over independent variables (so the
diagrams contain two independent loops). These should be simple to double check.
I will only give my results for these diagrams, not the sunset diagrams for now. These diagrams should
cancel independently of the sunset diagrams (a fact confirmed by a paper of Zumino).
But I can't get it to work!
These diagrams either have the form of two circles touching each other or two circles connected by
line (forming a dumbell).
These diagrams are all proportional to the integral
[tex] I \equiv i g^2 \int D(z-z) D(w-w) [/tex]
where D is just the usual boson propagator. I will quote all my results in terms of I .
CONTRIBUTION FROM L1
Diagram with two A loops: -3I/2
Diagram with one A loop and one B loop: -I
Diagram with two A loops: -3I/2
CONTRIBUTION FROM L2^2
Dumbell diagram with two A loops: 9 I/2
Dumbell diagram with one A loop and one B loop: 3 I
Dumbell diagram with two B loops: I/2
CONTRIBUTION FROM L3^2
Dumbell diagram, with two fermion loops: 8 I
CONTRIBUTION FROM L4^2
Because there is a gamma 5, there are no dumbell type contribution
CONTRIBUTION FROM L2 L3
Contribution with one A loop and one fermion loop: - 12 I
Contribution with one B loop and one fermion loop: -4 I
CONTRIBUTION FROM L3 L4 is identically zero.
SUM = -4 I
Now, can anyone check any of this??
I am trying to do what is (almost) the simplest SUSY calculation one can think of: the calculation of the vacuum energy in the Wess-Zumino model. The result shoudl be zero but I don't get that.
Since SUSY is "beyond the standard model" physics, I decided to cross-post my question here.
Let me start by asking a simpler question and see if anyone can help.
Let me break up the Wess-Zumino interactions into four terms
[tex] L_1 = - \frac{1}{2} g^2 (A^2 + B^2)^2 [/tex]
[tex] L_2 = - M g (A^3 + A B^2) [/tex]
[tex] L_3 = - g A \overline{\Psi} \Psi[/tex]
[tex] L_4 = - ig B \overline{\Psi} \gamma_5 \Psi [/tex]
where A and B are scalar fields and Psi is a Majorana spinor, although for the terms I want to check in this post, this makes no difference, they can be treated as Dirac spinors.
I consider the contributions to the vacuum energy of order g^2 so I calculate the time
ordered expectation values of
[tex] i L_1 - \frac{1}{2} ( L_2^2 + L_3^2 + L_4^2 + 2 L_2 L_3 + 2 L_2 L_4 + 2 L_3 L_4 ) [/tex]
There are two main classes of diagrams: diagrams in which three lines connect two distinct points.
(i.e. "sunset" diagrams). These are a bit more tricky.
Simpler diagrams are those that contain two loops over independent variables (so the
diagrams contain two independent loops). These should be simple to double check.
I will only give my results for these diagrams, not the sunset diagrams for now. These diagrams should
cancel independently of the sunset diagrams (a fact confirmed by a paper of Zumino).
But I can't get it to work!
These diagrams either have the form of two circles touching each other or two circles connected by
line (forming a dumbell).
These diagrams are all proportional to the integral
[tex] I \equiv i g^2 \int D(z-z) D(w-w) [/tex]
where D is just the usual boson propagator. I will quote all my results in terms of I .
CONTRIBUTION FROM L1
Diagram with two A loops: -3I/2
Diagram with one A loop and one B loop: -I
Diagram with two A loops: -3I/2
CONTRIBUTION FROM L2^2
Dumbell diagram with two A loops: 9 I/2
Dumbell diagram with one A loop and one B loop: 3 I
Dumbell diagram with two B loops: I/2
CONTRIBUTION FROM L3^2
Dumbell diagram, with two fermion loops: 8 I
CONTRIBUTION FROM L4^2
Because there is a gamma 5, there are no dumbell type contribution
CONTRIBUTION FROM L2 L3
Contribution with one A loop and one fermion loop: - 12 I
Contribution with one B loop and one fermion loop: -4 I
CONTRIBUTION FROM L3 L4 is identically zero.
SUM = -4 I
Now, can anyone check any of this??