Valence electrons of a transition element

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The discussion focuses on the valence electrons of transition elements, specifically using Iron (Fe) as an example with the electron configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d6. It addresses the confusion over which subshell, 4s or 3d, has higher energy, noting that the 3d subshell is filled later but the 4s has a higher principal quantum number. The consensus suggests that the valence electrons for transition metals are typically found in the outermost s subshell, leading to the conclusion that Iron has 2 valence electrons. Additionally, it is clarified that for transition elements, the valence electrons are determined by the electrons in the highest energy level, which includes both s and p subshells when applicable. Understanding these principles is essential for accurately determining valence electrons in transition metals.
reyrey389
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Valence electrons of a transition element...

Here is the electron config. for Iron (Fe) 1s2 2s2 2p6 3s2 3p6 4s2 3d6. I have two questions about this I've been on for hours...

#1 Which subshell (4s or 3d) has the highest subshell?
-You can say that the 3d has higher energy because you write it out later than the 4s (4s is filled before 3d)
-Then again, you can say that the 4s has higher energy because (4, the coefficient, tells us we are in the 4th energy level). 4 is the highest coefficient in that configuration, so the fourth energy level is the outermost.

So which should I follow - the first or the second?

#2 I have been also having trouble finding valence electrons for transition elements
In that configuration I displayed do we say that the valence electrons for Fe is 2? If so, will it always be in the sub shell of the highest coefficient (energy lvl). If I'm not mistaken this means to find the valence of a transition element you will look at the "s" subshell? BUT, since it is in the d-block it has filled the s, so the s will always be 2 for transition elements, so they all have 2 valence electrons?


Any help would be appreciated :)
 
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reyrey389 said:
Here is the electron config. for Iron (Fe) 1s2 2s2 2p6 3s2 3p6 4s2 3d6. I have two questions about this I've been on for hours...

#1 Which subshell (4s or 3d) has the highest subshell?
-You can say that the 3d has higher energy because you write it out later than the 4s (4s is filled before 3d)
-Then again, you can say that the 4s has higher energy because (4, the coefficient, tells us we are in the 4th energy level). 4 is the highest coefficient in that configuration, so the fourth energy level is the outermost.

So which should I follow - the first or the second?

Electrons are filled according to The Aufbau's principle ie n+l rule (small L not 1)

the orbital with higher value of n+l has higher energy and is filled later
l = 0 for s
l = 1 for p
l = 2 for d
l = 3 for f
 


reyrey389 said:
#2 I have been also having trouble finding valence electrons for transition elements
In that configuration I displayed do we say that the valence electrons for Fe is 2? If so, will it always be in the sub shell of the highest coefficient (energy lvl). If I'm not mistaken this means to find the valence of a transition element you will look at the "s" subshell? BUT, since it is in the d-block it has filled the s, so the s will always be 2 for transition elements, so they all have 2 valence electrons?

Well my knowledge might be wrong for this one but i think that valance electrons are no. of electrons in outermost energy level

i.e if configuration was 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4

so valence electrons will be 6 (2 in 4s and 4 in 4p)

(do you know what is wrong about confi.: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5 ? :biggrin: think about it)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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