Validate the Stefan Boltzmann equation

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Homework Help Overview

The discussion revolves around validating the Stefan Boltzmann equation through an experimental setup involving temperature, emissivity, and irradiance measurements. The original poster presents calculations related to the irradiance at a specified temperature and emissivity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the measured irradiance using a correction factor based on emissivity and temperature. Participants raise questions about the assumptions made regarding emissivity and the application of the correction factor.

Discussion Status

Participants are actively engaging with the original poster's calculations, providing clarifications and questioning the reasoning behind certain assumptions. There is a productive exchange regarding the interpretation of the correction factor and its impact on the measured irradiance.

Contextual Notes

There is a noted assumption that the thermopile measures 0 W/m2 at a specific temperature, which influences the calculations and understanding of the correction factor. The discussion also highlights the importance of distinguishing between measured and real values of irradiance.

tomadevil
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Homework Statement


You are performing an experiment to validate the Stefan Boltzmann equation. What irradiance would you measure at a temperature of 109C? The emissivity of your thermal heat source is 0.81 and your thermopile measures 0 W/m2 at 27 C when directed towards a blackbody. Submit your answer in units of W/m2, do not include the units in your answer.

Answer tolerance is +/- 0.2%.

Homework Equations


E=σeT^4

3. The Attempt at a Solution

I presume I have to work out a correction factor like this:
Ec=081*5.67E-8*300^4=372 W/m2
Then calculate measured irradiance:
E=5.67E-8*382^4*1=1207
Then I have to add the correction factor Ec to E to get the measured irradiance (Em):
Em=Ec+E=1579 w/m2

Am I doing it right?

Thanks for your answers.
 
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Hello,

1. Why do you assume the emissivity to be 1 when the temperature is 382 K?
2. Why do you add (and not subtract) the correction factor? Just think that your zero is at 372 W/m2.
 
1. Ohh, I get it know. I used 1 because of the blackbody, but I know now that is irrelevant. :)
2.I added the correction factor because the thermopile should measure 0 at 0 Kelvin. Therefore, the measured irradiance is always less by 372 W/m2.
 
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Exactly, the measured E must be less than the real by 372 W/m2. So, Emeasured=Ereal-Ecorrection.

Your equation implies that the measured E is bigger than the real E (by 372 W/m2).
 
Ohh, yes. I understand it know. Thank you! :-)
 

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