Vapor Pressure of saturated/unsaturated solution

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SUMMARY

The discussion centers on the vapor pressure of saturated and unsaturated NaCl aqueous solutions at the same temperature. According to Raoult's law, the vapor pressure of water (PH2O) above the unsaturated solution (solution 2) is greater due to its higher mole fraction of solvent (XH2O). The saturated solution (solution 1) has a lower vapor pressure and a higher boiling point. As water evaporates from the saturated solution, the mole fraction of water remains constant because some NaCl precipitates, while the mole fraction of the unsaturated solution decreases.

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  • Understanding of Raoult's law and its application in solutions
  • Knowledge of vapor pressure concepts in chemistry
  • Familiarity with mole fractions and their significance in solution chemistry
  • Basic principles of boiling point elevation in solutions
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  • Investigate the behavior of saturated vs. unsaturated solutions during evaporation
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Joshua Kenny
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Homework Statement

:

As the picture shows, there are two NaClaq solutions. One is saturated while the other is not and both of them are at the same temperature. There are three questions asked:
a) Above which solution is the vapor pressure of water, PH2O, greater? Explain.
b) Above one of these solutions, the vapor pressure of water, PH2O, remains constant, even as water evaporates from solution. Which solution is this? Explain.
c) Which of these solutions has the higher boiling point? Explain.


2. Homework Equations

As Raoult's law states: Psolution=Psolvent*Xsolvent
where Xsolvent is the mole fraction of the solvent in the solution. In this case, Xsolvent is XH2O.[/B]

The Attempt at a Solution



**For question a), solution (2) has a greater PH2O value because the amount of solute (in this case NaCl) is less than that of solution (1) therefore Xsolvent of solution (2) is greater than that of solution (1).

**For question c), solution (1) has a smaller PH2O value and therefore the boiling point of solution (1) would be higher than that of solution (2).[/B]

I'm left confused by question b) because I cannot prove how PH2O could remain constant. I would be glad if someone could explain the logic of this question. Please check as well if the previous answers/explanations for question a) and c) are appropriate or not.
 

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I've made a mistake for question a) & c)


For question a), solution (2) has a greater PH2O value because the amount of solute (in this case NaCl) is less than that of solution (1) therefore Xsolvent of solution (2) is greater than that of solution (1).


For question c), solution (1) has a smaller PH2Ovalue and therefore the boiling point of solution (1) would be higher than that of solution (2).
 
What happens to the solutions as water evaporates? Describe both cases.
 
As water evaporates, the amount of solvent (water) in both solutions decreases. For solution (2) the mole fraction of water should decrease in value. If I'm not mistaken, for solution (1) (which is saturated), as the water evaporates, some of the salt solidifies as well in proportion. So, the mole fraction of solvent of solution (1) remains constant.

Is this correct?
 
Very good.
 
So the answer is definitely 2,1,1?
 
Joshua Kenny said:
One is saturated while the other is not
"Not saturated, saturated, saturated."
 
Thanks a bunch!
 

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