Variation Method for Higher Energy States

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SUMMARY

The variation method for approximating higher energy states requires that the trial function be orthogonal to lower energy eigenfunctions. According to Leonard Schiff, the general function orthogonal to the previous level eigenfunction is expressed as ψ - (UEo × ∫((UEo[conjug])ψ dτ)). The application of the projector P = (1 - ∑|i⟩⟨i|) to the trial wave function ensures that any linear combination of lower eigenstates is nullified, confirming the orthogonality condition. This method relies on the orthonormality of lower states, expressed as ⟨i|j⟩ = δij.

PREREQUISITES
  • Understanding of the variation method in quantum mechanics
  • Familiarity with eigenfunctions and eigenvalues
  • Knowledge of Hermitian operators and their properties
  • Basic grasp of orthonormality in quantum states
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  • Study the application of the variation method in quantum mechanics
  • Learn about projector operators in quantum systems
  • Explore the concept of orthonormal bases in Hilbert spaces
  • Investigate the implications of non-degenerate eigenstates in quantum mechanics
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Quantum mechanics students, physicists working on quantum state approximations, and researchers interested in advanced methods for calculating eigenvalues and eigenfunctions.

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The variation method for approximating the the ground state eigenvalue, when applied to higher energy states requires that the trial function be orthogonal to the lower energy eigenfunctions.In that respect this book I am referring(by Leonard Schiff) mentions the following function as the general function orthogonal to the previous level eigenfunction:

ψ - (UEo × ∫((UEo[conjug])ψ dτ)) for any general fn ψ

Can somebody prove the above function's orthogonality to UEo ? I have tried to do it but could not come up with it?
 
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This is simply the application of a projector
P = \bigg(1 - \sum\nolimits_{i=1}^M |i\rangle\langle i|\bigg)
to the trial wave function psi, where i sums over the lower energy eigenstates. For this to be valid, the lower states need to be orthonormal:
\langle i | j \rangle = \delta_{ij}
(it is always possible to choose a set of eigenvectors of a Hermitian operator in such a way that they are orthonormal to each other; for non-degenerate eigenstates the orthogonality comes automatically).

Now take a closer look at this projector and take into account the lower state orthogonality. You will easily see that if you add any linear combination of a lower eigenstate to psi, this linear combination will be zeroed out by P. Thus
\langle i|P \psi\rangle=0
for any lower eigenstate i and any wave function psi.
 
Thanks.Got it.
 

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