Vector Calculus Problem - Griffith Textbook

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The discussion revolves around a problem from Griffith's "Introduction to Electrodynamics," specifically Question 1.21, which involves the vector expression (A.∇)B. The initial approach suggested calculating the divergence of A and multiplying it by the components of B, but the solution manual indicates a different method. It clarifies that (A.∇)B represents the directional derivative, indicating how the field B changes in the direction of A. The distinction between (A.∇)B and B(∇.A) is emphasized, as they involve differentiating different components. The explanation ultimately resolves the confusion regarding the operator's application in vector calculus.
Bruce Dawk
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I have a problem in the Griffith textbook (Introduction to Electrodynamics), Question 1.21, where it asks what is the meaning of the vector (A.∇)B, my simplistic approach would be to calculate the divergence of A which should be a scalar and multiply it out by Bx,By,Bz) to compute the x component of the expression. However in the solution manual (available by searching Introduction to Electrodynamics Solutions and clicking on the Scribd link) it seems to be the other way around.

I just don't understand why this is, can someone clarify please?
 
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(A.∇)B and B(∇.A) are not equal because that operator acts to the right so in
(A.∇)B
B is differentiated while in
B(∇.A)
A is differentiated
 
Thanks all. Its quite clear now.
 

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