Vector Multiplication in a Triangle on the Cartesian Plane

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SUMMARY

The discussion focuses on vector multiplication within a triangle on the Cartesian plane, specifically calculating the cross products of vectors A, B, and C with magnitudes 16, 12, and 20, respectively. The magnitude of A x B is confirmed to be 192, with the direction along the -x axis. The use of determinants to compute cross products is emphasized, highlighting the non-commutative nature of vector multiplication. A mnemonic for remembering the relationships between unit vectors is also provided, aiding in the understanding of cross products.

PREREQUISITES
  • Understanding of vector algebra and cross products
  • Familiarity with determinants and matrix algebra
  • Knowledge of unit vectors (i, j, k) in three-dimensional space
  • Basic trigonometry, including sine and tangent functions
NEXT STEPS
  • Study the properties of vector cross products in three-dimensional space
  • Learn how to calculate determinants of 3x3 matrices
  • Explore applications of vector multiplication in physics and engineering
  • Practice solving problems involving vector magnitudes and directions
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on vector analysis and cross products, as well as educators seeking to enhance their teaching methods in these subjects.

Lucian09474
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Homework Statement



For the vectors in a Triangle, with a = 16, b = 12, and c = 20 what are

(a) the magnitude and (b) the direction of A x B

(c) the magnitude and (d) the direction of A x C

(e) the magnitude and (f) the direction B x C

this is Vector Multiplication.

Homework Equations


ABsin(ø)
pythagorean theorem
tan^-1 (y/x)
3. The Attempt at a Solution

16i x 12j = 192 (magnitude of A x B it is correct) and the direction is along the -x axis (believed)

since this is vector multiplication, I realized that the best way to do it was using the determinant. which is a value associated with a square matrix. We can get the above relations following matrix algebra procedures to calculate the determinant of a 3×3 matrix, which in favor ends up giving us the vector product. if I am not mistaken the vector product can be expressed by multiplying the vectors, now here is where the problem arises. multiplying vector is not commutative and when multiplying vectors you get a new one (on the Z direction?)
 
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You should learn the different results of the cross-products between the unit vectors.

A handy mnemonic (a memory device) is

i j k | i j

which translated means (reading from left to right):

i x j = k

j x k = i

k x i = j

if you read the mnemonic in reverse, from right to left, you get:

j x i = -k

i x k = -j

k x j = -i

Any unit vector crossed with itself is zero:

i x i = j x j = k x k = 0

This can be confirmed also by writing out the cross products using determinants.
 
ah Indeed thank you very much. surprise to find out that after all the attempts all of the answers were 192. and the directions were a little bit tricky but I got the right answer.

thanks for the guidance.
 

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