Vector Problem - Angle between two vectors

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To determine the angle between two vectors A and B with equal magnitudes of 55.0, where their sum equals 17.7j, the formula R = [A^2 + B^2 + 2ABcos(theta)]^1/2 can be applied. Since the resultant vector is purely in the y-direction, the x-components of both vectors must cancel each other out. The magnitudes of A and B are known, allowing for the calculation of cos(theta) using the rearranged formula. The challenge lies in identifying the correct components of the vectors to apply these equations accurately. Ultimately, solving for theta will provide the angle between the two vectors.
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Homework Statement



Vectors A-> and B-> have equal magnitudes of 55.0. If the sum of A-> and B-> is the vector 17.7 j, determine the angle between A-> and B->

Homework Equations



cos(theta) = {[A]^2 + ^2 - [A-B]^2}/2[A]

(sorry, not sure how to type out that formula!)

tan(theta) = (Ay + By)/(Ax + Bx)

R =[(Ax + Bx)^2 + (Ay + By)^2]^1/2

The Attempt at a Solution



This one I am not sure about how to start, at all. I plugged what I could into those formulas, but any answers I got were incorrect. I don't understand how I can find out any more information with what is given, namely the other components of the vector (the i for each, as well as discerning which values for j each vector has).
 
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Since resultant is 17.7j, it is along y-axis. So its magnitude is 17.7. Magnitude of A ans B 55.0 each.
Use the formula R = [ A^2 + B^2 + 2ABcos(theta)]^1/2 and find theta.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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