Vector sample problem -- Force components on a spring mechanism

AI Thread Summary
The discussion focuses on determining the spring force necessary for achieving a vertical resultant force, with calculations revealing a compressive force of 60N and a resultant force of 10800. Participants clarify that the exerted force was initially misinterpreted as being in pounds rather than newtons. The correct approach involves calculating the horizontal and vertical components of the forces and understanding that the spring must counteract the horizontal component to maintain verticality. The conversation also highlights the confusion regarding whether the spring is in tension or compression based on the applied forces. Ultimately, the goal is to establish the equilibrium condition for the spring mechanism.
sHatDowN
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Homework Statement
Resolve to its component
Relevant Equations
vector addition
Determine the amount and type (tensile or compressive) of the spring force so that the resulting force is a vertical force. Also get the resultant force.

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i find 60N (compressive)
and resultant forces is 10800
is that correct?
 
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sHatDowN said:
Homework Statement:: Resolve to its component
Relevant Equations:: vector addition

Determine the amount and type (tensile or compressive) of the spring force so that the resulting force is a vertical force. Also get the resultant force.

View attachment 323126

i find 60N (compressive)
and resultant forces is 10800
is that correct?
The exerted force is given in lb, not N.
How did you determine the spring is compressed?
How did you calculate the resultant?
 
haruspex said:
How did you determine the spring is compressed?
First, i calculate Fx,Then we apply opposite force.
haruspex said:
How did you calculate the resultant?
R=F2+Fx2-2(F)(Fx)cos120
 
Actually,Its √10800
=103.92
 
sHatDowN said:
Actually,Its √10800
=103.92

Your magnitude is ok. I would have just noted that for ##R## to be vertical the force applied by the spring is opposite the component of ##F## in the horizontal direction ##{}^+ \leftarrow, {}^+ \downarrow##:

$$ F_s = - F \cos 60° = -60 ~[\rm{lbf}]$$

$$R = F \sin 60° = 60 \sqrt{3} ~ [\rm{lbf}]$$

Which is what you have.

However, is the spring in tension or compression when it is applying the force ##F_s##?
 
Last edited:
sHatDowN said:
... Determine the amount and type (tensile or compressive) of the spring force so that the resulting force is a vertical force.
:oldconfused:

The represented guide for that wheel (pushing or pulling the spring) is limiting the direction in which the spring is receiving any force, which is horizontal, rather than vertical.
 
Lnewqban said:
:oldconfused:

The represented guide for that wheel (pushing or pulling the spring) is limiting the direction in which the spring is receiving any force, which is horizontal, rather than vertical.
Yes, you right thanks alot
 
Did you change your mind about it being in compression?
 
Yes, thanks alot.
 
  • #10
Lnewqban said:
:oldconfused:

The represented guide for that wheel (pushing or pulling the spring) is limiting the direction in which the spring is receiving any force, which is horizontal, rather than vertical.
You misunderstand the question. It is asking what horizontal force from the spring will produce a vertical force when combined with the applied force F (and whether the spring will be in tension or compression). Which is a complicated way of asking for the force on the spring in equilibrium.
 
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