Vector Space? Determine Axiom Satisfaction

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Homework Help Overview

The discussion revolves around determining whether a given set of vectors, defined by the relationship a2 = 3a1 + 1, qualifies as a vector space. Participants are exploring the axioms that define vector spaces and questioning the implications of specific axioms on this set.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the application of vector space axioms, particularly the commutative property of addition. There is confusion about whether the set satisfies the requirements for being a vector space, especially regarding closure under linear combinations.

Discussion Status

The conversation is ongoing, with some participants providing guidance on considering the closure of the set under linear combinations, while others are clarifying the distinction between vector spaces and free spaces. Multiple interpretations of the axioms are being explored.

Contextual Notes

There is uncertainty about the specific axioms being referenced and whether the set in question meets the criteria for a vector space. Participants are also discussing the implications of the relationship defining the set of vectors.

maiad
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Homework Statement


Determine whether set is a vector space. If not, give at least one axiom that is not satisfied.
the set of vectors <a1, a2> where a2 =3a1+1

The Attempt at a Solution



I'm not sure if this is a vector free space or not,, what I'm confused is about is how the a rule such as "x+y=y+x" can be applied. Would it just be a1 +a2 = a1 +(3a1 +1)=a2+a1=(3a1+1)+a1
 
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You want to consider the closeness of this set under arbitrary linear combination, including zero vector, etc.
 
you mean axioms for a free space?
 
maiad said:
you mean axioms for a free space?

I meant axiom for a vector space (closeness under linear combination), if that's not what you meant, ignore what I said.
 

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