I'm trying to solve this problem with different approaches. Link is here the answer is 0i + 0.0927j + 0.0232 k lb * Means DOT Method one: Find the force in scalar components. Then Take the cross product of two position vectors to get a normal vector (V) to the surface. THen take the unit vector of V. Then F(normal) = (V*F)V THis method worked F(normal)= 0i + 0.0927j + 0.0232 k lb Method 2: Find the force in scalar components. Draw a perpendicular line to the surface and by similar triangles the normal vector V is 8j + 2k. Take the units vector of V. Then F(normal) = (V*F)V THis method worked F(normal)= 0i + 0.0927j + 0.0232 k lb Method 3: This one i tried taking a position vector along the surface like from point A to point J. Position vector AJ = 0i-1j+4k. THen getting of units vector, unit vector eAJ = 0i - 0.2425j + 0.9701k. THen F(parallel)= (eAJ*F)eAJ F(normal) = F- F(parallel) F(normal) = -0.1231 i + 0.0927j + 0.0232 k lb THe only difference is the x-component, which differs a little. Is this answer still right? I didn;t round any numbers when calculating.