- #1

glid02

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A particles position is defined by the equation x=y^2/6 and it moves at a constant velocity in the y-direction of 3 in/s. Find the velocity and acceleration when x=6 in.

I know v=sqrt(vx^2+vy^2) and a is found the same way, but I have absolutely no idea how to find the velocity of in the x-direction through the equation.

The only way I can think to do it is find the change in the x position over a very small interval of time and go from there, but I know there's an easier way.

If anyone could give me a starting point it'd be great.

Thanks a lot.