- #1

Panda1321

A. "At time t2 = 23.2 s , what is the

*x*-component of the dog's velocity?"

Equations:

Vx= dx/dt Vy= dy/dt First, I tried to find the velocity at t2=23.2s by: V=at V=(0.45m/s^2)(23.2s)=10.44m/s

Therefore Vx=10.44m/s

However, this answer is incorrect and I am unable to understand how to find Vx with the data given. Can someone please explain how to solve this problem and if the magnitude and direction given from T1 to T2 is different than the angle formed by starting at the origin to T1? Thanks!