Velocity and Acceleration Question

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SUMMARY

The discussion focuses on calculating the displacement, velocity, and acceleration of a particle moving along the x-axis, described by the equation x = 2.6(t^5) - 1.3(t^7). To find the displacement from t = 0.0 s to t = 1.8 s, users should evaluate the position function at these times and compute the difference. Velocity is determined by taking the first derivative of the position function, while acceleration is found by taking the second derivative. Specific times for calculating velocity and acceleration include 1.0 s, 2.0 s, 3.0 s, and 4.0 s.

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Homework Statement


The position of a particle moving along the x-axis depends on the time according to the equation x = c(t^5) - b(t^7), where x is in meters and t in seconds. Let c and b have numerical values 2.6 m/s5 and 1.3 m/s7, respectively. From t = 0.0 s to t = 1.8 s, (a) what is the displacement of the particle? Find its velocity at times (b) 1.0 s, (c) 2.0 s, (d) 3.0 s, and (e) 4.0 s. Find its acceleration at (f) 1.0 s, (g) 2.0 s, (h) 3.0 s, and (i) 4.0 s.


2. The attempt at a solution
Do I try to take the derivative to try and get the velocity and acceleration answers?
And how do I find the displacement?
 
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mossfan563 said:

Homework Statement


The position of a particle moving along the x-axis depends on the time according to the equation x = c(t^5) - b(t^7), where x is in meters and t in seconds. Let c and b have numerical values 2.6 m/s5 and 1.3 m/s7, respectively. From t = 0.0 s to t = 1.8 s, (a) what is the displacement of the particle? Find its velocity at times (b) 1.0 s, (c) 2.0 s, (d) 3.0 s, and (e) 4.0 s. Find its acceleration at (f) 1.0 s, (g) 2.0 s, (h) 3.0 s, and (i) 4.0 s.2. The attempt at a solution
Do I try to take the derivative to try and get the velocity and acceleration answers?
And how do I find the displacement?

The displacement should be found by using the position function f(t) = x = c*t5 - b*t7 and then determining the difference between the two positions at the times given.

As to the rest of your question if velocity is [tex]\frac{dx}{dt}[/tex] and acceleration is [tex]\frac{dv}{dt}[/tex] then taking derivatives looks like a sound approach and then plug in the points asked for.
 

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