Velocity and displacement *sigh* Isimple! but seems comple

  • Thread starter Lexadis
  • Start date
  • #1
11
1

Homework Statement


A stone is thrown vertically up with a velocity of 20ms/s. The maximum height reached by the stone and the total time taken by it to fall on the ground are

(1) 20m and 2 s. (2) 20m and 4 s. (3) 40m and 2 s. (4) 40m and 4 s.

Homework Equations


The Attempt at a Solution


V = s/t
V = 20/1 (since the time taken for the stone is 2s to go up and then come falling down, I divided it by 2 and I chose the first answer as it seemed to get my favorable answer)
V = 20m/s.

But according to the scheme it's the second answer and I really don't understand how it can come, providing that even if they are divided you get the velocity 5m/s.
 
Last edited:

Answers and Replies

  • #2
435
13
S = So + Vo*t + (1/2)*a*t^2
V = Vo + a*t

These are the equations that you need to use where

So = initial distance from origin
Vo = initial velocity
a = acceleration

Thats all you need to know to solve this question
 

Related Threads on Velocity and displacement *sigh* Isimple! but seems comple

  • Last Post
Replies
6
Views
1K
  • Last Post
Replies
8
Views
6K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
10
Views
7K
  • Last Post
Replies
4
Views
2K
Replies
5
Views
2K
Replies
3
Views
1K
Replies
2
Views
1K
Replies
1
Views
1K
Top