Velocity Change When Hitting a Wall

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Discussion Overview

The discussion revolves around the change in velocity of an object when it collides with a wall, specifically focusing on the implications of contact time and the nature of the collision (elastic vs. inelastic). Participants explore various scenarios and assumptions related to the physics of collisions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the change in velocity during contact with the wall is equal to the negative of the initial velocity, assuming a perfectly inelastic collision.
  • Others argue that the time of contact (0.2 seconds) may not be significant in determining the change in velocity, particularly if the object stops completely upon impact.
  • A participant mentions that in real-world scenarios, objects typically do not stop dead and may rebound, thus complicating the analysis of velocity change.
  • One participant introduces the concept of elastic collisions, suggesting that the change in velocity could be twice the initial velocity in such cases.
  • Another participant emphasizes the importance of impulse and acceleration, indicating that time becomes relevant when calculating these quantities.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of the contact time and the nature of the collision, indicating that multiple competing perspectives remain unresolved.

Contextual Notes

Some assumptions about the nature of the collision (elastic vs. inelastic) and external factors (like air resistance and gravity) are not fully explored, leaving gaps in the discussion.

Who May Find This Useful

This discussion may be of interest to individuals studying physics, particularly those focused on mechanics and collision dynamics.

DeanBH
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if something is moving at a wall with a given velocity. and is in contact with the wall for say 0.2 seconds.

the chance in velocity for those 0.2 seconds would be (-) the velocity it hit it win?
 
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the chance in velocity for those 0.2 seconds would be (-) the velocity it hit it win?

?

Could you perhaps try again?
 
hypothetical

ignore resistances of air and things

if something is moving at a wall with a given velocity. and is in contact with the wall for say 0.2 seconds.

the change in velocity for those the time it is in contact will the wall, would be (-) the velocity it hit it with?

there's no point in being so picky when you know exactly what i mean
 
Last edited:
Hey … DeanBH … I didn't understand it either! :frown:

Still not sure I do … the 0.2 seconds seems irrelevant … :confused:

If the ball just squished against the walll and stopped dead, then the change in velocity would be (-) the velocity it hit it with.

If the collision was perfectly elastic, the change in velocity would be twice that.
 
In reality, almost nothing (aside from maybe a sandbag or a lead-filled snowshoe) will just stop dead with no rebound. Also, even those things would gain an immediate downward velocity due to gravity unless the wall is out in space somewhere.
 
The ball is thrown into the wall a specific angle, leaving the thrower's hands with a specific amount of force, traveling in an arc-like path to hit a wall, thus causing some of the energy to dissipate as sound and heat, and bouncing off the wall at a downward angle.

You gave a single number: 0.2 s. which defines how long the ball was in contact with the wall.

That number has absolutely no significance, whatsoever. All you've done here is give the image of a ball hitting a wall, here.
 
DeanBH said:
if something is moving at a wall with a given velocity. and is in contact with the wall for say 0.2 seconds.

the chance in velocity for those 0.2 seconds would be (-) the velocity it hit it win?

The change in velocity is called the acceleration. Say your object moves from left to right, then contracts the wall. The change in velocity, or acceleration is (-), as you say is in the other direction, from right to left. I think this is what you've been asking about.
 
Just think about it this way. [tex]\Delta V=V_{final}-V_{initial}[/tex] so, if the initial velocity is 5 m/s and it comes to a dead stop, [tex]\Delta V=-5m/s[/tex]. Assuming no mass loss, [tex]\Delta \vec{P}=m\Delta \vec{V}=\vec{F}\cdot t[/tex]

When doing impulse or the acceleration, that is when the time matters.
 

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