Velocity from a force time graph

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Homework Help Overview

The discussion revolves around determining the speed at which a woman leaves the ground during a vertical jump, using a force-time graph that represents the force exerted by the floor. The problem involves concepts from dynamics and impulse, particularly considering the forces acting on the woman, including gravity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss deriving mass from the force graph and calculating impulse from the area under the graph. There are questions about whether to consider the entire area or only the area above the gravitational force. Some participants explore the relationship between impulse and initial velocity.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationship between force, mass, and impulse. There is a recognition that the force of gravity must be accounted for when calculating the effective impulse. Multiple interpretations regarding the calculation of impulse are being explored.

Contextual Notes

Participants note that the woman starts from rest and that the force of gravity (her weight) must be considered in the calculations. There is uncertainty about how to accurately calculate impulse based on the graph provided.

TheFluffyDuck
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Homework Statement



The figure is a graph of the force exerted by the floor on a woman making a vertical jump.
At what speed does she leave the ground? Hint: The force of the floor is not the only force acting on the woman.

Homework Equations





The Attempt at a Solution



I am completely lost with this question. First I derived her mass from the 600N from the graph. Which was about 61.22kg

Then I calculated the Impusle from the area underthe graph, but where from? All the area or minus the forces of gravity? then I used:

Impulse= m(delta v)

But I am not getting anywhere :(
 

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Starting with this: Impulse= m(delta v)

Then delta v = Impulse/m, and delta v = v - vo, and vo = ?
 
Im guessing Vo is zero becasue she is jumping straight up?

Do I calculate Impulse to be the entire area under the graph or just a certain segment under the graph?
 
TheFluffyDuck said:
Im guessing Vo is zero becasue she is jumping straight up?
Correct. Standing she starts are rest.

Do I calculate Impulse to be the entire area under the graph or just a certain segment under the graph?
Weight which is a force, does not provide for acceleration. One has to consider the force in excess of the weight.
 
Astronuc said:
Correct. Standing she starts are rest.



Weight which is a force, does not provide for acceleration. One has to consider the force in excess of the weight.

Thanks for your replies.
So since F=mg, and I derived mass from 600/9.8. does that mean that the impusle is the area of the graph from anything that is >600n?
 
TheFluffyDuck said:
Thanks for your replies.
So since F=mg, and I derived mass from 600/9.8. does that mean that the impusle is the area of the graph from anything that is >600n?
The 600 N is her weight, when she is not moving, so the force in excess of 600 N goes toward accelerating her mass.
 
Another way of looking at this problem is to convert F(t) to a(t), since a(t) is just F(t)/m, however, one has to look at Fnet(t), which is the difference between Ftotal(t) and mg.
 

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