Car A and Car B and travelling towards each other from 220m apart. If car A travels at 20km/h, both cars will meet at 44.5m. If car A travels at 40km/h, both cars will meet at 76.6m. What is the initial velocity and constant acceleration of car B?
The Attempt at a Solution
For car B, the formulas just involve distance and velocity since we don't have any other information, V^2 = (V_0)^2 + 2a(x - x_0).
Since acceleration is constant, it just becomes V^2 = (V_0)^2, which is meaningless because they will be the same value since acceleration is constant.
If we try some other formula like x = x_0 + (v_0)t + 1/2at^2, we are left with 220 = 175.5t + (v_0)t, which again is meaningless because we don't have time. (Same with every other equation, it is impossible to solve for time also given the information.)
So the problem doesn't seem to have enough information, yet apparently there is a solution...how do you do this?