Velocity of atomic (hydrogen) electrons

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Discussion Overview

The discussion centers on the velocity of electrons in a hydrogen atom, exploring calculations and conceptual understandings related to atomic physics. Participants are questioning the velocity value of 242,000 m/s and the implications of electrons traveling at the speed of light.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification

Main Points Raised

  • One participant questions the validity of electrons traveling at the speed of light (c) and seeks clarification on how to calculate the velocity of hydrogen electrons.
  • Another participant suggests that measuring or calculating the mean momentum and kinetic energy of the atomic electron can lead to determining its velocity.
  • A mathematical expression is presented, indicating that the kinetic energy (mv²) is equal to 27 eV, leading to a calculation of velocity as a fraction of the speed of light.
  • A request for clarification on the equation mv²=27 eV is made, indicating a desire for deeper understanding of the relationship between kinetic energy and velocity.

Areas of Agreement / Disagreement

Participants express differing views on the velocity of electrons and the implications of their speeds, with no consensus reached on the calculations or the conceptual understanding of electron velocities in atomic physics.

Contextual Notes

The discussion includes assumptions about the definitions of kinetic energy and velocity, and the calculations presented may depend on specific conditions or interpretations that are not fully resolved.

nuby
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Hello,

I've been wondering about the velocity of hydrogen electrons. I've read that 242,000 m/s was the correct velocity, however, I thought electrons would travel at c. How does one calculate this number?

Thanks in advance.
 
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Why would/should electrons travel at c?

One can measure/calculate the mean momentum & kinetic energy of the atomic electron, then it is trival to obtain its velocity.
 
mv^2=27 eV, so [tex]v/c=\sqrt{27/500,000}[/tex]
 
Can you explain that equation, if you get a chance? Why does mv^2=27ev
Thanks.
 

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