Velocity of bowling ball after the collision

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SUMMARY

The discussion focuses on calculating the velocity of a bowling ball after a collision with a pin using the law of conservation of momentum. The bowling ball has a mass of 6.0 kg and an initial velocity of 3.0 m/s, while the pin has a mass of 0.50 kg and moves at a velocity of 4.0 m/s post-collision. The formula used is MV = mv + Mx, where x represents the final velocity of the bowling ball. By substituting the known values, one can determine the bowling ball's final velocity after the collision.

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MorallyObtuse
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Hi,

I just need this explained, please.

Homework Statement



A large bowling ball of mass 6.0 kg moving with a velocity 3.0ms-1 has ahead on collision with a single pin of mass 0.50 kg.If the pin moves with a velocity of 4.0ms-1,calculate the velocity of bowling ball after the collision.
 
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Are you familiar with conservation of momentum?
Momentum is mass times velocity.
The momentum of the system before hand equal the momentum of the system after the collision.

Try some equations with it.
 
Redd is absolutelly right:

The law of conservation of momentym states that:

Initial Momentum=Final Momentum

if M=mass of bowl and m=mass of pin, V=velovity of bowl and v=final velocity of pin then:

MV=mv+Mx where: x=final velovity of bowl.

Substitute values to get x.
Remember about units,
good luck.
 

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