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Dennydont

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## Homework Statement

A venturi tube is a means of measuring fluid velocity. One particular device consists of a level, circular pipe of radius 5.7 cm which at one point narrows to a radius of 3.7 cm. An ideal, incompressible liquid flows through the tube and the pressure difference between the wide and narrow parts is found to be 3.5 kN/m^2. If the density of the liquid is 1120 kg/m3 what is the velocity of the fluid in the wide part of the pipe?

ρ = 1120 kg/m^3

∆P = 3.5kN/m^2

narrow radius = 3.7cm

wide radius = 5.7cm

## Homework Equations

Continuity: ρA

_{1}v

_{1}= ρA

_{2}v

_{2}

Bernoulli: P + 1/2ρv^2 + ρgh

## The Attempt at a Solution

I tried finding v

_{1}by using the rearranging Bernoulli's equation v = √((2∆P)/ρ) = 2.5m/s

Then using continuity equation, tried to find v

_{2}which happened to equal 1.05m/s. Incorrect.

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