1. The problem statement, all variables and given/known data A venturi tube is a means of measuring fluid velocity. One particular device consists of a level, circular pipe of radius 5.7 cm which at one point narrows to a radius of 3.7 cm. An ideal, incompressible liquid flows through the tube and the pressure difference between the wide and narrow parts is found to be 3.5 kN/m^2. If the density of the liquid is 1120 kg/m3 what is the velocity of the fluid in the wide part of the pipe? ρ = 1120 kg/m^3 ∆P = 3.5kN/m^2 narrow radius = 3.7cm wide radius = 5.7cm 2. Relevant equations Continuity: ρA1v1 = ρA2v2 Bernoulli: P + 1/2ρv^2 + ρgh 3. The attempt at a solution I tried finding v1 by using the rearranging Bernoulli's equation v = √((2∆P)/ρ) = 2.5m/s Then using continuity equation, tried to find v2 which happened to equal 1.05m/s. Incorrect.