Velocity of Roller Coaster at Top of Loop - Find the Answer!

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SUMMARY

The velocity of a roller coaster at the top of a loop with a radius of curvature of 12 m can be determined using the forces acting on a passenger. At the top of the loop, the normal force exerted by the seat is 0.4 mg, where m is the mass of the passenger. By applying Newton's second law (ƩF = Fnet = ma) and the centripetal acceleration formula (ac = v²/r), the speed can be calculated as v = √(rg(0.4 + 1)), leading to a definitive speed calculation based on gravitational force.

PREREQUISITES
  • Understanding of Newton's second law (ƩF = Fnet = ma)
  • Knowledge of centripetal acceleration (ac = v²/r)
  • Familiarity with gravitational force (Fg = mg)
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the speed of the roller coaster using the derived formula v = √(rg(0.4 + 1))
  • Explore the effects of different radii on roller coaster speed
  • Investigate the role of gravitational force in circular motion
  • Learn about safety factors in roller coaster design
USEFUL FOR

Physics students, engineering students, and anyone interested in the mechanics of roller coasters and circular motion dynamics.

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Homework Statement


The radius of curvature of a loop-to-loop roller coaster is 12 m. At the top of the loop, the force the force that the seat exerts on a passenger of mass m is 0.4 mg. Find the speed of the roller coaster at the top of the loop.


Homework Equations


ƩF = Fnet = ma
ac = v2/r
Fg = mg


The Attempt at a Solution


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What are the forces acting at the top of the loop? Form an equation for this.
 

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