Velocity of the center of mass in constrained motion

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The discussion revolves around calculating the velocity of the center of mass in a constrained motion scenario. Initial calculations yielded different results for velocity, prompting a reevaluation of the components of velocity in both horizontal and vertical directions. The correct speed was confirmed to be 2.5 m/s, with clarification that speed differs from velocity as it lacks direction. Participants were encouraged to explore the geometric relationship of the motion, particularly through the concept of the "trammel of Archimedes." Understanding the locus of point P and its relation to the triangle formed in the motion was also emphasized.
Prabs3257
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Homework Statement
In the figure shown A and B are two blocks of mass 5 kg each they are restraint to move in horizontal and vertical direction respectively as shown in the figure they are connected by a rigid massless rod as shown in the figure P is the midpoint of the rod when the velocity of B E is 4 upwards then the speed of of p at this instant is
Relevant Equations
Vcom = m1v1+m2v2/m1+m2
I tried getting the velocity of a which by using constraint came out to be 3 and by using the eqn for vcom i got the ans as 3.5 i just want to confirm is this the correct answer
 

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I don't think you have the right answer. Write an equation for the position of A as a function of the position of B. Then find the velocity of A as a function of the velocity of B. How is the horizontal velocity component of P related to the velocity of A? How is the vertical velocity component of P related to the velocity of B?
 
tnich said:
I don't think you have the right answer. Write an equation for the position of A as a function of the position of B. Then find the velocity of A as a function of the velocity of B. How is the horizontal velocity component of P related to the velocity of A? How is the vertical velocity component of P related to the velocity of B?
is the ans 2.5 coz i think i got the vcom wrong but now if we like resolve the component of vcom in x and y and calculate vcomx and vcomy seperately and just take the resultant i think then it should be correct??
 
Prabs3257 said:
is the ans 2.5 coz i think i got the vcom wrong but now if we like resolve the component of vcom in x and y and calculate vcomx and vcomy seperately and just take the resultant i think then it should be correct??
Yes, 2.5 m/s. But the question should not describe this as a velocity - it is a speed. For velocity a direction should also be specified. Can you see what the direction would be? Hint: consider the distance from P to the origin.
 
haruspex said:
Yes, 2.5 m/s. But the question should not describe this as a velocity - it is a speed. For velocity a direction should also be specified. Can you see what the direction would be? Hint: consider the distance from P to the origin.
I don't know the direction can you please explain it to me
 
Prabs3257 said:
I don't know the direction can you please explain it to me
What is the locus of P?
 
haruspex said:
What is the locus of P?
I am guessing maybe its a straight line
 
Prabs3257 said:
I am guessing maybe its a straight line
Try googling "trammel of archimedes" and watch how the center of mass moves.
 
Prabs3257 said:
I am guessing maybe its a straight line
Consider the triangle APO (where O is the point at the bottom right corner). What shape would you call it? What does that tell you about the distance OP?
 

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