Velocity Selector Homework: Determine Proton Speed for No Deflection

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SUMMARY

The discussion centers on calculating the speed of a proton in a region with both electric and magnetic fields, specifically with an electric field strength of 1.30×105 V/m and a magnetic field strength of 2.30 T. To achieve no deflection, the magnetic force must counterbalance the electric force, leading to the equation F = qv x B. The solution requires determining the proton's velocity such that these forces are equal and opposite.

PREREQUISITES
  • Understanding of electric fields and their strengths
  • Knowledge of magnetic fields and their strengths
  • Familiarity with the Lorentz force equation (F = qv x B)
  • Basic principles of vector analysis in physics
NEXT STEPS
  • Calculate the electric force acting on the proton using F = qE
  • Determine the necessary proton speed using the equation v = E/B
  • Explore the implications of perpendicular vectors in electromagnetic fields
  • Review the concept of uniform motion in the context of charged particles
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the behavior of charged particles in electric and magnetic fields.

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Homework Statement



A proton enters a space in which there are both electric and magnetic fields. The electric field points vertically upward and the strength is 1.30×105 V/m. The magnetic field points horizontally to the right and the strength is 2.30 T.

The proton enters with a velocity vector that is perpendicular to both the electric and magnetic fields, and the magnetic force is opposite to the electric force.

Determine the proton speed such that the proton will pass through the space with no deflection, i.e., with a constant velocity vector.

Homework Equations



I am not sure what equation to use.

The Attempt at a Solution



Can someone please help? I'm not sure where to begin.
 
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Ryo124 said:

Homework Statement



A proton enters a space in which there are both electric and magnetic fields. The electric field points vertically upward and the strength is 1.30×105 V/m. The magnetic field points horizontally to the right and the strength is 2.30 T.

The proton enters with a velocity vector that is perpendicular to both the electric and magnetic fields, and the magnetic force is opposite to the electric force.

Determine the proton speed such that the proton will pass through the space with no deflection, i.e., with a constant velocity vector.

Homework Equations



I am not sure what equation to use.

The Attempt at a Solution



Can someone please help? I'm not sure where to begin.

F = qv x B

You will need to offset the electric force with the force created by qv x B.
 

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