A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.30 T. The field is then adjusted so that an electron will follow a circular path of the same radius when it is projected perpendicularly into the field with the same velocity that the proton had. What is the magnitude of the field used for the electron?
q electron= -1.60E-19 C
q proton= 1.60E-19 C
The Attempt at a Solution
If the velocity and radius are the same they cancel out but I can't set them equal to each other because the Bs are different, right?
What I'm i forgetting?