Velocity-time graph given. Plot acceleration vs time etc.

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The discussion revolves around analyzing a velocity-time graph to derive an acceleration versus time graph for an object moving along the x-axis. Participants are tasked with calculating the average acceleration over specified time intervals: from 5.00 s to 15.0 s and from 0 to 20.0 s. The calculations presented confirm the accuracy of the derived values. The focus remains on ensuring the correct interpretation of the velocity-time data to produce the required acceleration graph. Overall, the calculations and plotting of the graphs are deemed correct.
Alexanddros81
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Homework Statement


Serway Physics Section 2.4 Acceleration

15. A velocity-time graph for an object moving along the x-axis is shown in Figure P2.15.
(a) Plot a graph of the acceleration versus time. Determine the average acceleration of
the object (b) in the time interval t=5.00 s to t=15.0 s and (c) in the time interval t=0 to t = 20.0 s.

Homework Equations


Serway Physics Figure P2_15.jpg


The Attempt at a Solution



Serway Physics 2_15001.jpg

[/B]
Is my calculation correct?
 

Attachments

  • Serway Physics Figure P2_15.jpg
    Serway Physics Figure P2_15.jpg
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  • Serway Physics 2_15001.jpg
    Serway Physics 2_15001.jpg
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Alexanddros81 said:

Homework Statement


Serway Physics Section 2.4 Acceleration

15. A velocity-time graph for an object moving along the x-axis is shown in Figure P2.15.
(a) Plot a graph of the acceleration versus time. Determine the average acceleration of
the object (b) in the time interval t=5.00 s to t=15.0 s and (c) in the time interval t=0 to t = 20.0 s.

Homework Equations


View attachment 233466

The Attempt at a Solution



View attachment 233467
[/B]
Is my calculation correct?
It is correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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