Velocity vector addition problem

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SUMMARY

The velocity vector addition problem discussed involves calculating the angle at which a boat must travel to reach a point across a river while accounting for the river's current. The correct answer is an angle of 53.13 degrees downstream, derived from the vector sum of the boat's velocity relative to the river and the river's velocity relative to the banks. The geometry of the situation indicates that the river is 600 meters wide and 300 meters along the bank, leading to the calculation of the angle using the tangent function, where tan(α) = 1/2. The discussion emphasizes the importance of using vector addition correctly and understanding the reference frames involved.

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  • Understanding of basic vector addition principles
  • Familiarity with trigonometric functions, specifically tangent
  • Knowledge of reference frames in physics
  • Basic geometry related to right triangles
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evo13
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Homework Statement
Introduction physics
Relevant Equations
Vector addition
1.png


Hello, guys. Interesting riddle here.
I have no idea how to solve it. Tried different methods, but point is answer is always wrong,
exact answer Downriver, at an angle of 53.13(degree) to the bank.
That exercise is from
"Pohl’s Introduction to Physics"
 
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The basic idea is that the velocity of the boat relative to the banks is the vector sum of the velocity of the river relative to the banks and the velocity of the boat relative to the river.
 
Yes, and i can't get a right answer. Basic idea is that velocity of boat and river is the same magnitude, at least as i understand it
 
evo13 said:
Yes, and i can't get a right answer. Basic idea is that velocity of boat and river is the same magnitude, at least as i understand it
Let's see your calculations.
 
PS The given answer of 53.13 degress is correct.
 
1637226208606.png


Sorry for the sloppiness, this is just one of the solutions I tried
 
You know that the river is ##600m## wide and it's ##300m## along the bank from ##A## to ##B##. The angle ##\alpha## can be calculated from this geometry.

I.e. ##\tan \alpha = 1/2##

You should get the answer from that.
 
PeroK said:
You know that the river is ##600m## wide and it's ##300m## along the bank from ##A## to ##B##. The angle ##\alpha## can be calculated from this geometry.

I.e. ##\tan \alpha = 1/2##

You should get the answer from that.

Yep, i did that. ∠α is 26,565 degrees
AB = sqrt(45) is not relevant, sorry.
 
evo13 said:
Yep, i did that. ∠α is 26,565 degrees
AB = sqrt(45) is not relevant, sorry.
That gives you the direction relative to the bank. The question wants the direction relative to the water, which means you have to do vector addition.
 
  • #10
Sorry but vector addition is second part of my solving attempt, below horizontal line.
I don't understand what else i can do
 
  • #11
PS I don't see how you got 58.3 degrees. You should have got 63.4 degrees upstream as the direction relative to the bank. But, that is independent of the velocity of the river.
 
  • #12
lets try another explanation, more clear i hope
c5cbf771-1fba-492b-bee5-20fdedb30cc2.jpg
 
  • #13
Okay, I see what you've done. Why would ##a = b##?

Note that your diagram is based on the reference frame of the banks. It's difficult to indicate the velocity of the boat relative to the river on that diagram.

Vector addition is the way to go!
 
  • #14
if not a = b, than c = b. Right?
I tried this also
 
  • #15
evo13 said:
if not a = b, than c = b. Right?
I tried this also
Neither. Your fundamental problem is that ##c## is from the river's frame of reference and ##a## is from the banks frame of reference. You are mixing vectors from two reference frames in one diagram.

Even if these equations were to hold, they can't be shown in a single diagram.

Use vector addition!
 
  • #16
Ye, alright. Thank for the help.
I am clearly not understand the question than, English is not my native.
 
  • #17
evo13 said:
Ye, alright. Thank for the help.
I am clearly not understand the question than, English is not my native.
You do understand the question. You're trying a clever shorcut that doesn't work!
 

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