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gbean

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## Homework Statement

Fred's friends are in a boat. If they could travel perpendicularly to the shore, they could land at his position. However, a strong current vc is greater than the maximum vm of the motor. Find the magnitude of the angle, measured relative to the straight-across direction, at which his friends should point the boat to minimize the distance Fred has to walk.

a) arcsin (vm/vc)

b) arctan (vc/vm)

c) tan (vc/vm)

d) arctan (sqrt(vc/vm))

## Homework Equations

a^2 + b^2 = c^2

sin(theta) = opposite/hypotenuse (=> theta = arcsin(opposite/hypotenuse))

cos(theta) = adjacent/hypotenuse

tan(theta) = opposite/adjacent

vx = vcos(theta)

vy = vsin(theta)

v = vx+vy

## The Attempt at a Solution

I tried to draw this out and I get that the angle is represented by theta = arctan(vm/vc).

I don't know what I'm doing wrong, please help!

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