Velocity vectors for an object dropped from a moving plane.

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SUMMARY

The discussion focuses on calculating the velocity vectors for an object dropped from a horizontally moving airplane. The key equations used include x=(-g/2)t² + V₀t + x₀ and v=-gt + V₀, where g represents gravitational acceleration. The user initially struggled with determining the time it takes for the package to land, ultimately deriving the time as t = (2X₀/g)^(1/2) and the initial horizontal distance X₀ as v²/(2g). The user successfully resolved their issues and completed the calculations.

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Homework Statement


An airplane is dropping an aid package in a remote area. The plane is moving horizontally at speed 0 and the package lands a horizontal distance from where it was released by the plane.

a) Find the time it takes for the package to land. -This is were I'm having the problem and is mostly what is preventing me from doing the rest.

b) Find the altitude of the plane.

c) Find the velocity (vector) of the package when it lands.

d)Find the speed of the package when it lands.

Write your results in terms of 0, L, and g. Check the units/dimensions for each answer.


Homework Equations


x=(-g/2)t2+V0t+x0
v=-gt+V0
a=-g

The Attempt at a Solution


The acceleration in the y-vector is -g/2*t2 and it has an initial velocity of 0 because it is being dropped from a plane moving parallel to the ground. solving for t gave me t=(2X0/g)1/2 then solving for X0 I got X0=v2/2g which is just leading me in circle leaving me with variables that I can't find a value for and are not accepted in the answer.
 
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Nevermind i solved it.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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