Velocity Vs Time Conceptual Question

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SUMMARY

The discussion centers on interpreting a velocity versus time (VT) graph for two cars traveling on a two-lane road, as part of a homework assignment from MasteringPhysics.com. Key conclusions include that Car 1 stops at point B, Car 2 stops at point E, and both cars have the same velocity at point D. The participant expresses uncertainty about determining the exact positions of the cars due to a lack of numerical data, ultimately concluding that the problem does not provide sufficient information to ascertain their initial positions.

PREREQUISITES
  • Understanding of velocity versus time graphs
  • Knowledge of displacement calculation using area under the curve
  • Familiarity with concepts of acceleration and deceleration
  • Basic physics principles related to motion
NEXT STEPS
  • Study how to calculate displacement from velocity versus time graphs
  • Learn about the implications of initial conditions on motion analysis
  • Explore the concept of relative motion in physics
  • Review problem-solving strategies for physics homework on MasteringPhysics.com
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Students studying physics, particularly those tackling motion problems involving velocity versus time graphs, and educators seeking to enhance their teaching methods in kinematics.

neon612
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This is homework help, but I think all I need to learn is how to read a VT graph properly. My professor uses MasteringPhysics.com and this is one of the questions from the site. The way it works is: the student has 5 attempts to answer a question before it is counted wrong and I'm down to my last attempt. I'm hoping I've already figured out the right answer and I just need to make sure that what I think is the right answer actually is.

After each attempt it gave me some feedback saying "The location of the cars are unknown at this time. All that is known is their velocities." And that was for points A, B, C, and E.

Homework Statement


Two cars travel on the parallel lanes of a two lane road. The cars' motions are represented by the velocity versus time graph. Answer each of the questions with reference to the lettered times (A through E) marked on the graph. (graph attached)

http://img703.imageshack.us/img703/633/1011351.jpg

At which of the lettered times, if any, do the two cars pass?

The Attempt at a Solution


From my textbook and searching the net I've been able to figure out:

The two cars have the same velocity at point D
Car 1 stops at point B
Car 2 stops at point E

If I think about it as a east-west road, I come up with:
Car 1 is traveling west and slowing down until it gets to point B. Then it accelerates, heading east.

Car 2 is traveling west and slowing down until half a graph square before A. Then it speeds up heading east until point C, when it starts slowing down until point E. It stops at point E, and speeds up heading west.

I know the area under the curve will tell me the displacement. But how does that work if I'm not given any numbers to work with?

So, I guess the answer I keep coming up with is that the problem doesn't have enough information to figure an exact position. (To put it in the wording from Mastering Physics "Cannot be Determined")
 
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Ummm ... where's the graph?
 
Sorry, I thought I had attached it to the opening post.
 
Actually for answering this, i need to know do the 2 cars start from same point or matbe initial distance b/w them
 
cupid.callin said:
Actually for answering this, i need to know do the 2 cars start from same point or matbe initial distance b/w them

Actually, this is all the information I am given to solve the problem. There are other parts to answer (but I've already answered them):

When does car 1 stop? -> At B
when does car 2 stop? -> At E
And when do they have the same velocity -> at D
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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