- #1

rkslperez04

- 31

- 0

I think I have the hang off it but I want to make sure I am grasping the questions here.

**A rollar coaster is traveling on a horizontal track at 20 m/s. What is its speed after climbing the second hill.**

I understand this to be an Ei=Ef problem.

Here is my work:

1/2MVi^2 = 1/2MVf^2 + GH ( all the mass variables cancel out )

1/2(20)^2 = 1/2(Vf)^2 + (9.8)(15)

200 = 1/2(Vf)^2 + 147

53 = 1/2(Vf)^2

53*2 = Vf^2

106 = Vf^2

Sq rt 106 is 10 m/s = Vf

am I close? Please let me know.. I want the right answer but I also want to comperhend what's going with these. Just wanted you to know I am not looking for someone to do my work.. just nudge me along ;)

(got one for you too after this, also... a coeffencient of friction.. that one I will need someone to walk me through)