Verify Mean Value Theorem: f(x)=3x^2+6x+7 on [-2,3]

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SUMMARY

The discussion centers on verifying the Mean Value Theorem (MVT) for the function f(x) = 3x² + 6x + 7 over the interval [-2, 3]. The user correctly identifies that f(3) - f(-2) equals f'(x)(3 - (-2)), leading to the equation 45 = 30x + 30. The error identified was in the arithmetic, where the user mistakenly computed 45 - 30 as 5 instead of 15. The correct solution yields x = 1/2, confirming the application of the MVT.

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Verify that the function satisfies the hypotheses of the Mean Value Theorem on the given interval. Then find all numbers that satisfy the conclusion of the Mean Value Theorem.


f(x)=3x^2+6x+7 on [-2,3]

so f(3)-f(-2)=f'(x)(3+2)

i get 52-7=(6x+6)(5)

then 45=30x+30

then 5=30x

and x=1/6

where am i going wrong?
 
Physics news on Phys.org
You seem to have computed 45-30=5?!
 
oohhh my! thank you so much! i didnt see that !
 

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