- #1
rkslperez04
- 31
- 0
Hey everyone,
Im studying for a test and wanted to verify my problems. I thought I would dabble on the dark side of the textbook and try the even ones too.
Can you verify my answer?
Kelly :)
A 810kg car accelerates from rest to 27m/s in a distance of 120m. That is the magitudeof the aver net force acting on the car?
Here is what I did.
1) step up my list of info:
Vi = 0
Vf = 27 m/s
a =
t =
x = 120 m
2) Figured I needed the F=MA equation
I have the mass so solve for acceleration.
3) a = Vf^2 - Vi^2 / 2x... which is: 27^2 / 2*120 = 3.075 m/s^2
I plugged A into the equation
4) F = (810 kg)(3.0375 m.s^2)
F = 2460.375
? did I get it?
Im studying for a test and wanted to verify my problems. I thought I would dabble on the dark side of the textbook and try the even ones too.
Can you verify my answer?
Kelly :)
A 810kg car accelerates from rest to 27m/s in a distance of 120m. That is the magitudeof the aver net force acting on the car?
Here is what I did.
1) step up my list of info:
Vi = 0
Vf = 27 m/s
a =
t =
x = 120 m
2) Figured I needed the F=MA equation
I have the mass so solve for acceleration.
3) a = Vf^2 - Vi^2 / 2x... which is: 27^2 / 2*120 = 3.075 m/s^2
I plugged A into the equation
4) F = (810 kg)(3.0375 m.s^2)
F = 2460.375
? did I get it?
