Verify Solution of Matrix Row Reduction Problem

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SUMMARY

The discussion centers on the verification of a solution to a matrix row reduction problem, specifically achieving the Reduced Row Echelon Form (RREF) of a given matrix. The user successfully row reduced the matrix to RREF, resulting in the matrix [1 0 -1 -2; 0 1 2 3; 0 0 0 0]. They correctly identified that the vector (0,1,2,3) is a linear combination of the vectors (1,2,3,4) and (2,6,10,14), leading to the conclusion that the basis of row(A) is {(1,0,-1,-2), (0,1,2,3)}.

PREREQUISITES
  • Understanding of matrix row reduction techniques
  • Familiarity with Reduced Row Echelon Form (RREF)
  • Knowledge of linear combinations and vector spaces
  • Basic linear algebra concepts
NEXT STEPS
  • Study the properties of Reduced Row Echelon Form (RREF)
  • Learn about linear independence and basis in vector spaces
  • Explore applications of row reduction in solving systems of linear equations
  • Investigate the implications of dropping linearly dependent vectors in matrix analysis
USEFUL FOR

Students and educators in linear algebra, mathematicians focusing on matrix theory, and anyone involved in solving systems of linear equations or studying vector spaces.

temaire
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Homework Statement


http://img708.imageshack.us/img708/7309/10324398.jpg

The Attempt at a Solution


First I row reduced the matrix into the RREF and got

<br /> \left[ \begin{array}{cccc} 1 &amp; 0 &amp; -1 &amp; -2 \\ 0 &amp; 1 &amp; 2 &amp; 3 \\ 0 &amp; 0 &amp; 0 &amp; 0 \end{array} \right]<br />

(0,1,2,3) is a linear combinatin of (1,2,3,4) and (2,6,10,14) so you drop it. Therefore {(1,0,-1,-2), (0,1,2,3)} is a basis of row(A).

Am I correct?
 
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