1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Verifying whether my working is correct in showing Linear Independence

  1. May 23, 2012 #1
    1. The problem statement, all variables and given/known data
    I have attempted the questions below but am not sure if I am applying the method correctly to show linear dependence/independence.

    a)Show that the vectors
    e1=[1 1 0]T, e2=[1 0 1]T, e3=[0 1 1]T
    are linearly independent

    b) Show that the vectors
    e1=[1 1 0]T, e2=[1 0 -1]T, e3=[0 1 1]T
    are linearly independent

    (T = Transverse)

    2. Relevant equations
    The determinant


    3. The attempt at a solution
    I have attempted to find the determinant by putting the vectors in a 3x3 matrix and finding the determinant which when =0 should give linear dependence and when ≠0 give linear independence. My working and the questions are attached in a pdf file with this thread.

    I'd greatly appreciate any help
     

    Attached Files:

  2. jcsd
  3. May 23, 2012 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Do you know the basic definition of "independent", "dependent" vectors?

    A set of vectors [itex]\{v_1, v_2, \cdot\cdot\cdot, v_n\}[/itex] is "independent" if and only if in order to have [itex]a_1v_1+ a_2v_2+ \cdot\cdot\cdot+ a_nv_n\}[/itex], we must have [itex]a_1= a_2= \cdot\cdot\cdot+ a_n= 0[/itex].

    Here, such a sum would be of the form
    [tex]a_1\begin{bmatrix}1 \\ 1 \\ 0 \end{bmatrix}+ a_2\begin{bmatrix}1 \\ 0 \\ 1 \end{bmatrix}+ a_3\begin{bmatrix}0 \\ 1 \\ 1\end{bmatrix}= \begin{bmatrix}0\\ 0 \\ 0 \end{bmatrix}[/tex]
    Of course multiplying the scalars and adding that is the same as
    [tex]\begin{bmatrix}a_1+ a_2 \\ a_1+ a_3 \\a_1+ a_2\end{bmatrix}= \begin{bmatrix}0 \\ 0 \\ 0\end{bmatrix}[/tex]

    which, in turn, is equivalent to the three equations
    [itex]a_1+ a_2= 0[/itex], [itex]a_1+ a_3= 0[/itex], [itex]a_1+ a_2= 0[/itex]

    [itex]a_1= a_2= a_3= 0[/itex] is obviously a solution to that system of equations. Is it the only one (if so the vectors are independent. If there exist another, non "trivial" solution, they are dependent).

    Of course, one can determine whether or not a system of equations is has unique solution by looking at the determinant of coefficients. As you say, these sets of vectors are independent (I would not say "independence exists").
     
  4. May 23, 2012 #3
    I do not understand by what you mean by "As you say, these sets of vectors are independent (I would not say "independence exists")"
    From my calculations I found the first question to be independent and the second dependent. What do you mean you would not say independence exists?

    I don't understand how a1+a2=0 or a1+a3=0
    if you add these up;
    a1+a2= [1 1 0] + [1 0 1] = [2 1 1]
    a1+a3= [1 1 0] + [0 1 1] = [1 2 1]

    how do you get them to = 0?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Verifying whether my working is correct in showing Linear Independence
  1. Verify My Proof Please (Replies: 4)

  2. Linear independance (Replies: 5)

Loading...