Vertical acceleration due to car going over speed bump

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SUMMARY

The vertical acceleration of a car going over a speed bump measuring one foot wide and four inches tall can be calculated using the formula Acceleration = dv/dt. Initial calculations suggested an acceleration of approximately 25g, which was deemed excessive. After considering factors such as speed (initially set at 30 mph, later adjusted to 20 mph) and the design of the speed bump, the corrected maximum vertical acceleration was determined to be 5.4g. Key considerations include the radius of the bump and the impact of tire absorption on the overall acceleration experienced by the vehicle.

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  • Understanding of basic physics concepts, particularly acceleration and forces.
  • Familiarity with vehicle dynamics and suspension systems.
  • Knowledge of speed bump design standards and their impact on vehicle performance.
  • Ability to perform calculations involving radius and acceleration.
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  • Research "Vehicle dynamics and suspension systems" to understand how shocks affect acceleration.
  • Study "Speed bump design standards" to learn about the implications of different designs on vehicle performance.
  • Explore "Calculating acceleration from radius and height" for more accurate assessments in similar scenarios.
  • Investigate "Effects of tire absorption on vehicle dynamics" to comprehend how tires influence acceleration and comfort.
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Engineers, automotive designers, and physics students involved in vehicle dynamics, suspension analysis, and safety design related to speed bumps.

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Homework Statement


Find the vertical acceleration of a car going over a speed bump a foot wide and 4 inches tall.

Homework Equations


Acceleration = dv/dt

The Attempt at a Solution


http://imgur.com/55t2WCQI am getting an answer that is around 25*g
I know this is way too much.
neglecting the shocks on the car, what assumptions am I messing up that would allow me to do this problem correctly? This isn't homework, rather a small part of a larger project where I need the forces to do failure analysis.
 
Last edited:
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Complete said:

Homework Statement


Find the vertical acceleration of a car going over a speed bump a foot wide and 4 inches tall.

Homework Equations


Acceleration = dv/dt

The Attempt at a Solution


http://imgur.com/55t2WCQ


I am getting an answer that is around 25*g
I know this is way too much.
neglecting the shocks on the car, what assumptions am I messing up that would allow me to do this problem correctly? This isn't homework, rather a small part of a larger project where I need the forces to do failure analysis.
attachment.php?attachmentid=58711&stc=1&d=1368514163.jpg

Was that 20 mph speed given ?

Was anything else given, which you have not included here?
 

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Nothing was given other than the thing I am designing should be able to withstand the force of going over a speed bump. I originally had it at 30mph but my number was way higher so I lowered it hoping that would be my problem. I looked up online the higher end dimensions of a speed bump and got a smaller width of 1 foot and a height of no more than 4 inches. Thanks for the reply.
 
Yes, but speed bumps and speed humps are different. Also I was assuming I should use the bump where the force would be greatest. maybe I was going too high with 4'' but http://www.innoplast.com/sbs6.html was closer to what I was imagining going over.
 
r = (4² + ¼*12²)/2*4 =6.5
Yes, but I see naught where you are going with this?
 
Complete said:
r = (4² + ¼*12²)/2*4 =6.5
Yes, but I see naught where you are going with this?

I was going to work out the acceleration another way but the small radius caught my eye. If curved as per the original drawing it would have very steep sides - perhaps not as bad as a vertical kerb but still.
 
Article here suggests humps are typically designed to reduce speeds to 15mph where as bumps target around 5mph.

http://www.dmgov.org/Departments/Engineering/PDF/FAQ9_Speed_Bumps_and_Humps.pdf

Speed bumps, on the other hand, have a more abrupt design. They consist of a portion of raised pavement, but because of their abruptness their use is very restricted. In fact, most speed bumps are found in parking lots and or along private roadways. Their height is typically between three and six inches, and they are usually only one to three feet long. Speed bumps produce substantial driver discomfort, damage to the vehicle suspension, and/or loss of control if encountered at too high a speed. This is one reason speed bumps are not used on public roadways. In general, vehicles must slow to about five miles per hour or less for a speed bump (compared to 15 mph for a speed hump).
 
  • #10
Thanks. This has been helpful.
 
  • #11
attachment.php?attachmentid=58728&stc=1&d=1368554212.jpg

Fixed it and I got 5.4g as my maximum acceleration vertical. Thanks again.
 

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  • #12
Complete said:
Fixed it and I got 5.4g as my maximum acceleration vertical.
Sure, but acceleration of what? The tyres, certainly, but a bit less for the wheel as a whole and much less for the vehicle as a whole.
Also, passenger discomfort is not just a matter of peak acceleration. It's a compound oscillator problem. With a short bump, a low speed can produce a much larger amplitude rise in the vehicle than a higher speed.
 

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