Maximum Acceleration of Stacked Blocks on Vertical Spring

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SUMMARY

The discussion centers on calculating the maximum acceleration of a stacked system of blocks on a vertical spring. A 5 kg block with a spring constant of 1000 N/m supports a 3 kg block. The key insight is that the maximum acceleration occurs when the normal force on the 3 kg block becomes zero, which can be derived using Newton's second law: ma = N - mg. The normal force can be expressed as kx, where k is the spring constant and x is the displacement of the spring.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of spring mechanics, specifically Hooke's Law
  • Familiarity with forces acting on objects in vertical motion
  • Basic algebra for solving equations
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  • Study the application of Newton's second law in dynamic systems
  • Learn about Hooke's Law and its implications in oscillatory motion
  • Explore the concept of normal force and its role in contact forces
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Students studying physics, particularly those focusing on mechanics, engineers working with spring systems, and educators teaching dynamics concepts.

fiziksfun
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An 5 kg block is fastened to the top of a vertical spring (perpendicular to the floor) with a spring constant of 1000 N/m. A 3 kg block sits on top of the 5 kg block.

The springs are pushed down so that they oscillate.

I need help finding the magnitude of the maximum acceleration the blocks can obtain while still remaining in contact. I have no idea where to begin.

Any suggestions!? Help please!
 
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HINT: Consider the forces acting on the 3kg block, which force will be zero when the blocks lose contact?
 
Ok so when the blocks lose contact, the force of the spring-mass will be equal to the force of gravity on the 3 kg block.

M(3)*a=-2mg, is this correct?
 
You've still not answered my first question. What are the forces acting on the top block?
 
Last edited:
The forces acting on the block are gravity and the force of the spring, correct? Or friction??
 
fiziksfun said:
The forces acting on the block are gravity and the force of the spring, correct?
Correct, but what I was trying to get at is that the force of the spring acts through the normal force exerted on the block. Hence, the net force acting on the block is N - mg. Can you now use this information to write an equation using Newton's second law?
 
ma = N - mg

but what is the magnitude of the normal force ??!? kx !?
 
fiziksfun said:
ma = N - mg
Correct! And what do you know about the normal force when the block leaves the surface of the 5kg block?
 

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