Vertically Stretched Spring w/ Hanging Mass.

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SUMMARY

The discussion focuses on a vertical spring with a spring constant (k) of 53 N/m and a 2.5 kg mass attached, initially positioned at the 15 cm mark on a ruler. The objective is to determine the new position of the spring's end when the mass is attached, requiring the calculation of the spring's stretch and the force exerted by the spring at equilibrium. Key equations include the potential elastic energy formula (1/2 kx²) and the relationship between net force and spring force (1/2 kx = Fnet). The user seeks a systematic approach to solve for the spring's extension and the tension force.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of potential energy in elastic systems
  • Familiarity with free body diagrams (FBD) and equilibrium conditions
  • Ability to apply conservation of energy principles
NEXT STEPS
  • Calculate the spring's stretch using Hooke's Law (F = kx)
  • Explore the relationship between gravitational force and spring force at equilibrium
  • Learn about potential energy transformations in spring systems
  • Investigate the use of free body diagrams to analyze forces in static equilibrium
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and spring dynamics, as well as educators seeking to enhance their understanding of elastic forces and equilibrium conditions.

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Homework Statement


A spring with a k=53N/m hangs vertically next to a ruler. The end of the spring is next to the 15cm mark on the ruler. If a 2.5kg mass is now attached to the end of the spring, where will the end of the spring line up with the ruler marks?

k=53 N/m
m=2.5m
y0=0.15m

Homework Equations


Potential Elastic Energy =1/2kx^2
1/2kx = Fnet

The Attempt at a Solution


Drew a diagram with a spring and mass at two different positions. Having trouble getting the force of tension when the spring is at equilibrium (FT1. But I've tried using conservation of energy, but can't figure out how to get either the acceleration at equilibrium or the force of tension at the spring's equilibrium. I've also tried using kinematics, but without either a time interval or acceleration I can't get a value for V1. Other than that I've tried a number of different ways of substituting equations into other equations to try to get some of these missing values, but I can't seem to get what I am looking for. I'm looking for a blueprint for how to get the answer to this question.
 
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If x0(=15 cm) represents the location of the bottom of the spring when no weight is attached, and x represents the location of the bottom of the spring when the weight is attached, how much has the spring stretched? What is the force exerted by the spring on the mass? From a FBD, how does this compare with the weight of the mass (assuming the mass has been moved downward by hand)?

chet
 

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