Vertices of triangle, multi-problems

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SUMMARY

The discussion focuses on the geometric properties of triangle ABC with vertices A(2a,0), B(2b,0), and C(0,2). Participants derive the equations of the sides: AB: y=0, AC: x+ay=2a, and BC: x+by=2b. The challenge lies in finding the equations of the medians, which are correctly identified as x+(2a-b)y=2a, x+(2b-a)y=2b, and 2x+(a+b)y=2(a+b). A key point clarified is that the median connects a vertex to the midpoint of the opposite side, emphasizing the importance of midpoints in median calculations.

PREREQUISITES
  • Understanding of triangle geometry and properties
  • Knowledge of coordinate geometry
  • Familiarity with equations of lines
  • Ability to calculate midpoints of line segments
NEXT STEPS
  • Study the derivation of median equations in triangles
  • Learn about centroid properties and calculations in triangles
  • Explore the relationship between medians and triangle area
  • Investigate the use of coordinate geometry in solving geometric problems
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Students studying geometry, mathematics educators, and anyone interested in understanding triangle properties and median calculations.

rocomath
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Vertices of triangle ABC are A(2a,0), B(2b,0), C(0,2).

a) Find the equations of the sides (check, did that)

AB: y=0
AC: x+ay=2a
BC: x+by=2b

I'm having trouble with b)

Show that the equations of the medians are: x+(2a-b)y=2a, x+(2b-a)y=2b, 2x+(a+b)y=2(a+b)

Ok, they're not referring to the midpoints of AB, AC, and BC? I think that's where my mistake is. The median is point of intersection where a line intersects each line at each line's midpoint and meets at a common center point inside the triangle?
 
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Part of your objective is to find the midpoint of each side because that is an essential component of Median of a Triangle. The point in the interior of the triangle at which the medians intersect is of no concern in the answer.
 
rocomath said:
Vertices of triangle ABC are A(2a,0), B(2b,0), C(0,2).

a) Find the equations of the sides (check, did that)

AB: y=0
AC: x+ay=2a
BC: x+by=2b

I'm having trouble with b)

Show that the equations of the medians are: x+(2a-b)y=2a, x+(2b-a)y=2b, 2x+(a+b)y=2(a+b)

Ok, they're not referring to the midpoints of AB, AC, and BC? I think that's where my mistake is. The median is point of intersection where a line intersects each line at each line's midpoint and meets at a common center point inside the triangle?

No. A "median" of a triangle is the line segment from one vertex to the midpoint of the opposite side. For example, the midpoint of AB is (a+b, 0) and C is (0,2). What is the equation of that line?
 
Your answer to part a) ...

... isn't quite right. Hint: What is the y-int of lines connecting A and C ? A and B?
 
Sorry, I meant B and C?
 
tmclary said:
... isn't quite right. Hint: What is the y-int of lines connecting A and C ? A and B?

tmclary said:
Sorry, I meant B and C?
?

The equations given were AC: x+ay=2a and BC: x+by=2b with A= (2a,0), B= (2b, 0), and C= (0, 2). When x= 2a, the first equation gives 2a+ ay= 2a or y= 0 and when x= 0 it gives ay= 2a or y= 2. When x= 2b, the second equation gives 2b+ by= 2b or y= 0 and when x= 0 it gives by= 2b so y= 2. Exactly what is wanted.
 
D'oh

Yup, yup and yup. Sheesh, the careless algebra mistakes I can make are embarrassing. thanks H.O.V.
 

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